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monitta
3 years ago
14

Please help meh ill mark braniliest!!​

Mathematics
1 answer:
Crazy boy [7]3 years ago
3 0

Answer:

its -15 !!! its easy!!!!

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15 POINTS ITS MY TEST ALREADY MISSING PLEASE HELP ON THIS ONE
const2013 [10]
Melanie walked 2.2 miles. Cathy walked 1.75 times as far. This means that you need to do 2.2 * 1.75 which equals 3.85. To find how much further, do 3.85 - 2.2 which equals 1.65. Therefore Cathy walked 1.65 more miles than Melanie.
3 0
2 years ago
At work jenine helps 6 customers every 40 minutes. How many customers can she expect to help in 240 minutes before her break?
Lady bird [3.3K]

Answer: 36 customers

Step-by-step explanation:

I'm pretty sure because you have to multiply 40 x 6 which is 240 and 6 x 6 which is 36 to get your answer.

7 0
3 years ago
I need help on this please help :)
GenaCL600 [577]

Answer:

Because they are different and have different MCQ scqare UNIT.

Step-by-step explanation:

Make me brainliest please :)

4 0
3 years ago
The joint probability density function of X and Y is given by fX,Y (x, y) = ( 6 7 x 2 + xy 2 if 0 < x < 1, 0 < y < 2
fredd [130]

I'm going to assume the joint density function is

f_{X,Y}(x,y)=\begin{cases}\frac67(x^2+\frac{xy}2\right)&\text{for }0

a. In order for f_{X,Y} to be a proper probability density function, the integral over its support must be 1.

\displaystyle\int_0^2\int_0^1\frac67\left(x^2+\frac{xy}2\right)\,\mathrm dx\,\mathrm dy=\frac67\int_0^2\left(\frac13+\frac y4\right)\,\mathrm dy=1



b. You get the marginal density f_X by integrating the joint density over all possible values of Y:

f_X(x)=\displaystyle\int_0^2f_{X,Y}(x,y)\,\mathrm dy=\boxed{\begin{cases}\frac67(2x^2+x)&\text{for }0

c. We have

P(X>Y)=\displaystyle\int_0^1\int_0^xf_{X,Y}(x,y)\,\mathrm dy\,\mathrm dx=\int_0^1\frac{15}{14}x^3\,\mathrm dx=\boxed{\frac{15}{56}}

d. We have

\displaystyle P\left(X

and by definition of conditional probability,

P\left(Y>\dfrac12\mid X\frac12\text{ and }X

\displaystyle=\dfrac{28}5\int_{1/2}^2\int_0^{1/2}f_{X,Y}(x,y)\,\mathrm dx\,\mathrm dy=\boxed{\frac{69}{80}}

e. We can find the expectation of X using the marginal distribution found earlier.

E[X]=\displaystyle\int_0^1xf_X(x)\,\mathrm dx=\frac67\int_0^1(2x^2+x)\,\mathrm dx=\boxed{\frac57}

f. This part is cut off, but if you're supposed to find the expectation of Y, there are several ways to do so.

  • Compute the marginal density of Y, then directly compute the expected value.

f_Y(y)=\displaystyle\int_0^1f_{X,Y}(x,y)\,\mathrm dx=\begin{cases}\frac1{14}(4+3y)&\text{for }0

\implies E[Y]=\displaystyle\int_0^2yf_Y(y)\,\mathrm dy=\frac87

  • Compute the conditional density of Y given X=x, then use the law of total expectation.

f_{Y\mid X}(y\mid x)=\dfrac{f_{X,Y}(x,y)}{f_X(x)}=\begin{cases}\frac{2x+y}{4x+2}&\text{for }0

The law of total expectation says

E[Y]=E[E[Y\mid X]]

We have

E[Y\mid X=x]=\displaystyle\int_0^2yf_{Y\mid X}(y\mid x)\,\mathrm dy=\frac{6x+4}{6x+3}=1+\frac1{6x+3}

\implies E[Y\mid X]=1+\dfrac1{6X+3}

This random variable is undefined only when X=-\frac12 which is outside the support of f_X, so we have

E[Y]=E\left[1+\dfrac1{6X+3}\right]=\displaystyle\int_0^1\left(1+\frac1{6x+3}\right)f_X(x)\,\mathrm dx=\frac87

5 0
3 years ago
A tractor-trailer travels 205.296 miles in 3.12 hours. What is the speed at which the tractor-trailer is traveling?
taurus [48]
Speed=distance/time
distance=205.296
time=3.12

speed=205.296/3.12=65.8

answer is 65.8 miles per hour
6 0
3 years ago
Read 2 more answers
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