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irinina [24]
3 years ago
7

Helppp1!!!! i need this for my homework

Mathematics
2 answers:
castortr0y [4]3 years ago
4 0

Answer:

12p + 48= 48 (p+12)

Step-by-step explanation:

VashaNatasha [74]3 years ago
3 0
First person is right mark him Brainliest
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Leo reads 60 pages in 2 hours. how long will it take home to read 17 pages at th same rate​
nexus9112 [7]
It takes him 1 hour to read 30 pages so he’ll be reading 15 pages in 30 minutes so
17 pages in 34 minutes
6 0
3 years ago
What is the volume of the pyramid shown below?
kykrilka [37]

Step-by-step explanation:

Given:

h=7in

w=9in

l=6in

Required:

v=?

Formula:

<em>v</em><em>=</em><em>l</em><em>*</em><em>w</em><em>*</em><em>h</em>

Solution:

v=l*w*h

v=6in*9in*7in

v=54in^2*7in

v=378in^3

Hope this helps ;) ❤❤❤

3 0
3 years ago
Find the length of the third side of the right triangle. Give an exact answer and an approximation to three decimal places if ne
trasher [3.6K]

Answer:

a = 32

Step-by-step explanation:

This is a right triangle and the square value of hypotenuse is equal to sum of square value of other two side lengths

68^2 = 60^2 + a^2

4624 = 3600 + a^2

4624 - 3600 = a^2

1024 = a^2 find the root for both sides

32 = a

8 0
2 years ago
For what value of a is (a,9) a solution for the equation y=2x+1?
Ivahew [28]

Answer:

Step-by-step explanation:

(a,9).......we dont know " a " (or x) but we do know y...it is 9

so sub in 9 for y and solve for x

y = 2x + 1

9 = 2x + 1

9 - 1 = 2x

8 = 2x

8/2 = x

4 = x <======= ur answer is D

5 0
3 years ago
Plss answer!! <br>MERRY Christmas!!! <br>Critical Question. AAAAA​
liberstina [14]

Answer:

Step-by-step explanation:

abc = 1

We have to prove that,

\frac{1}{1+a+b^{-1}}+\frac{1}{1+b+c^{-1}}+\frac{1}{1+c+a^{-1}}=1

We take left hand side of the given equation and solve it,

\frac{1}{1+a+\frac{1}{b}}+\frac{1}{1+b+\frac{1}{c}}+\frac{1}{1+c+\frac{1}{a}}

Since, abc = 1,

\frac{1}{c}=ab and c = \frac{1}{ab}

By substituting these values in the expression,

\frac{1}{1+a+\frac{1}{b}}+\frac{1}{1+b+\frac{1}{c}}+\frac{1}{1+c+\frac{1}{a}}=\frac{1}{1+a+\frac{1}{b}}+\frac{1}{1+b+ab}+\frac{1}{1+\frac{1}{ab}+\frac{1}{a}}

                                       =\frac{b}{b+ab+1}+\frac{1}{1+b+ab}+\frac{ab}{ab+1+b}

                                       =\frac{1+b+ab}{1+b+ab}

                                       =1

Which equal to the right hand side of the equation.

Hence, \frac{1}{1+a+b^{-1}}+\frac{1}{1+b+c^{-1}}+\frac{1}{1+c+a^{-1}}=1

5 0
3 years ago
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