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Bogdan [553]
4 years ago
15

The diameter is a circle is 16in. Find it’s circumference in terms of π. C= ________in

Mathematics
1 answer:
DIA [1.3K]4 years ago
7 0
<h3><u>S</u><u> </u><u>O</u><u> </u><u>L</u><u> </u><u>U</u><u> </u><u>T</u><u> </u><u>I</u><u> </u><u>O</u><u> </u><u>N</u><u> </u><u>:</u></h3>

According to the question,

  • Diameter of circle = 16 in

We are asked to calculate it’s circumference in terms of π.

★ Circumference of circle = 2πr

___________________________________

Let us first calculate the radius of the circle.

→ Diameter = 2 × Radius

→ 16 in = 2r

→ r = 16 in ÷ 2

→ r = 8 in

___________________________________

Substituting values in the formula of circumference,

→ C = 2πr

→ C = (2 × π × 8) in

→ C = 16π in

<u>Therefore</u><u>,</u><u> </u><u>1</u><u>6</u><u>π</u><u> </u><u>inches</u><u> </u><u>is</u><u> </u><u>the</u><u> </u><u>required</u><u> </u><u>answer</u><u>.</u>

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M is a directly proportional to r cubed when r=4 M=160
Paraphin [41]

Answer:

1) When r = 2, M = 20.

2) When M  = 540, r = 6.

Step-by-step explanation:

M is a directly proportional to r cubed

This means that the equation for M has the following format:

M = ar^3

In which a is a multiplier.

When r=4 M=160.

We use this to find a. So

M = ar^3

160 = a(4^3)

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a = 2.5

So

M = 2.5r^3

1) work out the value of M when r=2

M = 2.5*2^3 = 2.5*8 = 20

When r = 2, M = 20.

2) work out the value of r when M=540

M = 2.5r^3

540 = 2.5r^3

r^3 = \frac{540}{2.5}

r^3 = 216

r = \sqrt[3]{216}

r = 6

When M  = 540, r = 6.

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Step-by-step explanation:

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Given that f(x) = x2 − 4x − 3 and g(x) = the quantity of x plus three, over four, solve for f(g(x)) when x = 9. 
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Hello! To find the composition of functions we want to take all the x values in f(x) and replace them with g(x). Then to solve for a specific value, we plug in that value for x. Let's look at the steps below
f(x)=x^{2} -4x-3
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So we find
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