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notka56 [123]
3 years ago
12

Find the value of x in the triangle shown below​

Mathematics
2 answers:
aleksandr82 [10.1K]3 years ago
7 0

\huge\bold{Given:}

Length of the perpendicular = 3

Length of the hypotenuse = 6

\huge\bold{To\:find:}

The value of ''x".

\huge\bold{Solution:}

\longrightarrow{\purple{A.\:x\:=\:√27}} 

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}

Using Pythagoras theorem, we have

( Perpendicular )² + ( Base )² = (Hypotenuse)²

\longrightarrow{\blue{}}  ( 3 )² + {x}^{2} = ( 6 )²

\longrightarrow{\blue{}}  9 + {x}^{2} = 36

\longrightarrow{\blue{}}  {x}^{2} = 36 - 9

\longrightarrow{\blue{}}  {x}^{2} = 27

\longrightarrow{\blue{}}  x = \sqrt{27}

Therefore, the length of the missing side "x" is \sqrt{27}.

\huge\bold{To\:verify :}

\longrightarrow{\green{}} ( 3 )² + ( √27 )² = ( 6 )²

\longrightarrow{\green{}} 9 + 27 = 36

\longrightarrow{\green{}} 36 = 36

\longrightarrow{\green{}} L. H. S. = R. H. S.

Hence verified. ✔

\huge{\textbf{\textsf{{\orange{My}}{\blue{st}}{\pink{iq}}{\purple{ue}}{\red{35}}{\green{♡}}}}}

Alla [95]3 years ago
4 0
The answer is A, square root of 27=5.196
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