Question

Find the value of x in the triangle shown below​

Answer 1

$\huge\bold{Given:}$

Length of the perpendicular = 3

Length of the hypotenuse = 6

$\huge\bold{To\:find:}$

The value of ''$x$".

$\huge\bold{Solution:}$

$\longrightarrow{\purple{A.\:x\:=\:√27}}$ 

$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}$

Using Pythagoras theorem, we have

( Perpendicular )² + ( Base )² = (Hypotenuse)²

$\longrightarrow{\blue{}}$  ( 3 )² + ${x}^{2}$ = ( 6 )²

$\longrightarrow{\blue{}}$  9 + ${x}^{2}$ = 36

$\longrightarrow{\blue{}}$  ${x}^{2}$ = 36 - 9

$\longrightarrow{\blue{}}$  ${x}^{2}$ = 27

$\longrightarrow{\blue{}}$  $x$ = $\sqrt{27}$

Therefore, the length of the missing side $"x"$ is $\sqrt{27}$.

$\huge\bold{To\:verify :}$

$\longrightarrow{\green{}}$ ( 3 )² + ( √27 )² = ( 6 )²

$\longrightarrow{\green{}}$ 9 + 27 = 36

$\longrightarrow{\green{}}$ 36 = 36

$\longrightarrow{\green{}}$ L. H. S. = R. H. S.

Hence verified. ✔

$\huge{\textbf{\textsf{{\orange{My}}{\blue{st}}{\pink{iq}}{\purple{ue}}{\red{35}}{\green{♡}}}}}$

Answer 2

The answer is A, square root of 27=5.196