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zlopas [31]
3 years ago
14

Multiply choice ! help

Mathematics
1 answer:
Lostsunrise [7]3 years ago
6 0

Answer:

put it all in tiger algebra it will give you all of the answers

Step-by-step explanation:

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Thank you for helping me
dedylja [7]

Answer:

thank you for giving me points ;)

Step-by-step explanation:

4 0
3 years ago
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Help me with this problem please
Ymorist [56]

Answer:

-15

Step-by-step explanation:

3^2 - 3 x [(5^2 - 9) / 2 ]

9 - 3 x [(25 - 9) / 2]

9 - 3 x (16/2)

9 - 3 x 8

9 - 24

-15

5 0
3 years ago
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Find the area.<br> 7 in.<br> 5 in.<br> 12 in.
vitfil [10]

Answer and Step-by-step explanation:

<u>The area formula for a trapezoid is as follows:</u>

A = \frac{a + b}{2}h

Where:

A = Area

a = top side length

b = bottom side length

h = height

<u>Plug in the values given to you into the equation and solve.</u>

A = \frac{7 +12}{2}(5)

A = \frac{19}{2}(5)

A = \frac{95}{2}

<u>A = 47.5 </u>in.^2<u> is the answer.</u>

<u></u>

<em><u>#TeamTrees #PAW (Plant And Water) #ALM (All Lives Matter)</u></em>

6 0
3 years ago
6 people consists of 3 married couples. Each couple wants to sit with older partner on the left.
Lera25 [3.4K]

a. The first part asks for how many ways they can be seated together in a row. Therefore we want the permutations of the set of 6 people, or 6 factorial,

6! = 6 * 5

= 30 * 4

= 360 * 2 = 720 possible ways to order 6 people in a row

b. There are two cases to consider here. If the doctor were to sit in the left - most seat, or the right - most seat. In either case there would be 5 people remaining, and hence 5! possible ways to arrange themselves.

5! = 5 * 4

= 20 * 3

= 120 * 1 = 120 possible ways to arrange themselves if the doctor were to sit in either the left - most or right - most seat.

In either case there are 120 ways, so 120 + 120 = Total of 240 arrangements among the 6 people if the doctor sits in the aisle seat ( leftmost or rightmost seat )

c. With each husband on the left, there are 3 people left, all women, that we have to consider here.

3!  = 3 * 2 6 ways to arrange 3 couples in a row, the husband always to the left

8 0
3 years ago
I just need help with this problem
sashaice [31]
Keeping in mind that the area of a circle is πr².

the actual area will just be the area of the rectangular backyard plus the pool, namely (10*20) + (π15²), which gives us an actual area of 200 + 225π.

now, we know the model and actual are on a 1:20 ratio.

\bf \cfrac{model}{actual}\qquad 1:20\qquad \cfrac{1}{20}\qquad \qquad \cfrac{m}{200+225\pi }=\cfrac{1}{20}&#10;\\\\\\&#10;m=\cfrac{(200+225\pi )1}{20}\implies m=\cfrac{200+225\pi }{20}\implies m=\cfrac{200}{20}+\cfrac{225\pi }{2}&#10;\\\\\\&#10;m=10+112.5\pi
5 0
4 years ago
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