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3 years ago

क)18.069

Mathematics

1 answer:

Burka [1]3 years ago

3 0

Huh? im not sure i understand the question fully

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Of the 50 U.S. states, 4have names that start with the letter W . What percentage of U.S. states have names that start with the

Verizon [17]

8% of US states start with W

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3 years ago

Sammy is an hourly employee who makes $26 per hour as an elevator technician. He is paid overtime $13 for every hour that he wor

oksian1 [2.3K]

Answer:

364$

Step-by-step explanation:

you multiply 26 times 13 which equals 364

8 0

4 years ago

Choose the system of inequalities that best matches the graph below.

lapo4ka [179]

Answer:

D) $y\:$ , $y\:>\:-x$

Step-by-step explanation:

The blue boundary line has a y-intercept of 2 and a slope of 2.

It has equation : $y=2x+2$

Since the boundary line is not solid and the lower half plane of this line is shaded, its inequality is

$y\:$

The blue boundary line passes through the origin and has slope $-1$ .

Its equation is $y=-x.$

Since the boundary line is not solid and the right half-plane is shaded, its inequality is $y\:>\:-x$

The correct choice is D.

4 0

4 years ago

f(x) = 3 cos(x) 0 ≤ x ≤ 3π/4 evaluate the Riemann sum with n = 6, taking the sample points to be left endpoints. (Round your ans

Kruka [31]

Answer:

$\int_{0}^{\frac{3 \pi}{4}}3 \cos{\left(x \right)}\ dx\approx 3.099558$

Step-by-step explanation:

We want to find the Riemann sum for $\int_{0}^{\frac{3 \pi}{4}}3 \cos{\left(x \right)}\ dx$ with n = 6, using left endpoints.

The Left Riemann Sum uses the left endpoints of a sub-interval:

$\int_{a}^{b}f(x)dx\approx\Delta{x}\left(f(x_0)+f(x_1)+2f(x_2)+...+f(x_{n-2})+f(x_{n-1})\right)$

where $\Delta{x}=\frac{b-a}{n}$ .

Step 1: Find $\Delta{x}$

We have that $a=0, b=\frac{3\pi }{4}, n=6$

Therefore, $\Delta{x}=\frac{\frac{3 \pi}{4}-0}{6}=\frac{\pi}{8}$

Step 2: Divide the interval $\left[0,\frac{3 \pi}{4}\right]$ into n = 6 sub-intervals of length $\Delta{x}=\frac{\pi}{8}$

$a=\left[0, \frac{\pi}{8}\right], \left[\frac{\pi}{8}, \frac{\pi}{4}\right], \left[\frac{\pi}{4}, \frac{3 \pi}{8}\right], \left[\frac{3 \pi}{8}, \frac{\pi}{2}\right], \left[\frac{\pi}{2}, \frac{5 \pi}{8}\right], \left[\frac{5 \pi}{8}, \frac{3 \pi}{4}\right]=b$