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2 years ago

8

1 What is the equation of the line parallel to 8x - 16y= -14 and passing through (3, 0)?

1 answer:

andreev551 [17]2 years ago

7 0

Answer:

8x -16y = 24

Step-by-step explanation:

8x - 16y= -14

A parallel line (i.e. same slope) will be: 8x - 16y= c

We have to find the value of "c".

If it passes through (x, y) = (3, 0) ⇒ 24 - 0 = c,

so equation is 8x -16y = 24

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A company makes a cone-shaped container with a height of 15 in. The area of its base is about 78.8in.2 Approximately what is the

MakcuM [25]

Answer:

Approximately the volume of cone-shaped container is <u>393 in³</u>.

Step-by-step explanation:

Given:

A company makes a cone-shaped container with a height of 15 in.

The area of its base is about 78.8 in².

Now, to get the cone-shaped container volume.

So, we find the radius first by using formula:

Let the radius be $r.$

<u><em>(Using the value π = 3.14)</em></u>

$A_{B}=78.8\ in^2.$

$A_{B}=\pi r^2$

$78.8=3.14\times r^2$

<em>Dividing both sides by 3.14 we get:</em>

<em /> $25.09=r^2$ <em />

<em>Using square root on both sides we get:</em>

$5.00=r$

$r=5\ in.$

Thus, the radius ( $r$ ) = 5 in.

<u>The height (</u> $h$ <u>) = 15 in.</u>

Now, to get the volume of the cone-shaped container we put formula:

$Volume=\pi r^2\frac{h}{3}$

$Volume=3.14\times 5^2\times \frac{15}{3} \\\\Volume=3.14\times 25\times 5\\\\Volume=392.50\ in^3.$

Therefore, approximately the volume of the cone-shaped container is 393 in³.

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2 years ago

What is the distance between P(12, 4) and Q(-8, 2)

abruzzese [7]

$\huge{\boxed{2 \sqrt{101}}}$

The distance formula is $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ , where $(x_1, y_1)$ and $(x_2, y_2)$ are the points.

Substitute in the points. $\sqrt{(2-4)^2+(-8-12)^2}$

Subtract. $\sqrt{(-2)^2+(-20)^2}$

Solve the exponents. $\sqrt{4+400}$

Add. $\sqrt{404}$

Now, we can simplify this square root just a little bit. $404$ has a square factor of $4$ . $\sqrt{404}=\sqrt{4}*\sqrt{101}$

The square root of $4$ equals $2$ . $\boxed{2 \sqrt{101}}$

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2 years ago

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100 points.<br> Find the surface area of the triangular prism. The unit is cm^2

nikklg [1K]

First we find the area of the two triangles on each side (keep in mind that they are equal/congruent to each other):

(24*10)/2 = 120 cm^2

Then you find the areas of the three rectangles that are left:

24*19 = 456 cm^2
26*19 = 494 cm^2
10*19 = 190 cm^2

Finally, to find the surface area of the prism:

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ruslelena [56]

It is the absolute value

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erastova [34]

Answer:

36 minutes is the answer!

Step-by-step explanation:

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