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muminat
3 years ago
10

The table shows the outputs, y, for different inputs, x: Input (x) 8 12 14 16 Output (y) 8 12 16 16 Part A:Do the data in this t

able represent a function? Justify your answer. (3 points) Part B: Compare the data in the table with the relation f(x) = 8x − 5. Which relation has a greater value when x = 8? (2 points) Part C: Using the relation in Part B, what is the value of x if f(x) = 19? (5 points)
Mathematics
1 answer:
Nataly_w [17]3 years ago
7 0
A. yes, the data represents a function because u have no repeating x values. A function cannot have repeating x values...they can have repeating y values, just not the x ones.

B. table : (8,8)(12,12)(14,16)(16,16)
                look at ur points...when x = 8, y = 8...so the table, when x = 8 has a 
                value of 8
relation : f(x) = 8x - 5....when x = 8
              f(8) = 8(8) - 5
              f(8) = 64 - 5
              f(8) = 59....and the relation has a value of 59
Therefore, the relation has a greater value when x = 8 <==

C. f(x) = 8x - 5...when f(x) = 19
     19 = 8x - 5
      19 + 5 = 8x
     24 = 8x
     24/8 = x
     3 = x <==
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Step-by-step explanation:

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IRINA_888 [86]

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Quiz
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Answer:

h=-6 k=-30

Step-by-step explanation:

y=x^2+12x+6

\mathrm{The\:vertex\:of\:an\:up-down\:facing\:parabola\:of\:the\:form}\:y=ax^2+bx+c\:\mathrm{is}\:x_v=-\frac{b}{2a}

a=1,\:b=12,\:c=6

x_v=-\frac{b}{2a}

x_v=-\frac{12}{2\cdot \:1}\\

x_v=-6\\

\mathrm{Plug\:in}\:\:x_v=-6\:\mathrm{to\:find\:the}\:y_v\:\mathrm{value}

y_v=\left(-6\right)^2+12\left(-6\right)+6\\y_v=-30\\\left(-6,\:-30\right)

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3 years ago
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