Answer:
(-5,1)
Step-by-step explanation:
Answer:
We start with y = g(x) = f(x)
First, we have a vertical stretch by a factor of 2.
A vertical strech by a factor of A will be g(x) = A*f(x)
then in this case A = 2, so we have g(x) = 2*f(x)
Now we have it shifted left by 8 units.
We know that f(x - A) shift right the graph by A units (A positive), here A = 8.
then we have: g(x) = 2*f(x - 8)
Now we want shift up 3 units, if we have y = f(x) we can shift the graph up by A units as: y = g(x) + A (for A positive)
Then we have: g(x) = 2*f(x - 8) + 3
now, our function was f(x) = Log₅(x)
then g(x) = 2*log₅(x - 8) + 3.
A polar coordinate is that which can be written as (r, θ) where r is the radius and θ is the angle.
The radius, r, is also the hypotenuse of the right triangle that can be formed. Hence, it can be calculated through the equation,
r² = x² + y²
If we are to simplify this for the r alone, we have,
r = sqrt (x² + y²)
Substituting the known values,
r = sqrt ((4)² + (-4)²) = 4√2
The x and y can be related through the trigonometric function, tangent.
tan θ = y/x
To solve for θ
θ = tan⁻¹(y/x) = tan⁻¹(-4/4) = -45° = 315°
Hence, the polar coordinate is <em>(4√2, 315°)</em>
We use quadratic formula for that one
remember that √-1=i
so
for
ax^2+bx+c=0
so
given
5x^2-6x+2=0
a=5
b=-6
c=2
