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viktelen [127]
3 years ago
12

What is the answer to this problem? 7(g+5)=105

Mathematics
2 answers:
yawa3891 [41]3 years ago
7 0

Answer:

g = 10

7g + 35 = 105

.       -35    -35

7g = 70

g = 10

Liono4ka [1.6K]3 years ago
3 0

Answer:

g = 10

Step-by-step explanation:

Distribute 7 to the parentheses:

7(g + 5) = 105

7g + 35 = 105

Solve for g:

7g + 35 = 105

7g = 170

g = 10

So, the answer is g = 10

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Solve the linear system if 3x+4y-z=-6 5x+8y+2z=2. -x+y+z=0
Anni [7]
We are given with three equations and three unknowns and we need to solve this problem. The solution is shown below:
Three equations are below:
3x + 4y - z = -6
5x + 8y + 2z = 2
-x + y + z = 0

use the first (multiply by +2) and use the second equation:
2 (3x+4y -z = -6)  => 6x + 8y -2z = -12
                               + ( 5x + 8y +2z = 2)
                                  ------------------------
                                     11x + 16y = -10  -> this the fourth equation

use the first and third equation:
 3x + 4y -z = -6
+ (-x + y + z =0)
-------------------------
        2x + 5y = -6 -> this is the fifth equaiton

use fourth (multiply by 2) and use fifth (multiply by -11) equations such as:
2 (11x + 16y = -10)   => 22x + 32y = -20  -> this is the sixth equation
-11 (2x + 5y = -6)    => -22x -55y = 46   -> this is the seventh equation

add 6th and 7th equation such as:
   22x + 32y = -20
+(-22x - 55y = 66)
---------------------------
             - 23y = 46
               <span>   y = -2

solving for x, we have:
</span>2x + 5y = -6 
2x = -6 - 5y
2x = -6 - (5*(-2))
2x = -6 +10
2x = 4
x=2

solving for y value, we have:
-x + y + z =0
z = x -y 
z = 2- (-2)
z =4

The answers are the following:
x = 2
y = -2
z = 4
5 0
4 years ago
including a 8% sales tax an inn charges $140.40 per night find the inns nightly cost before tax is added
Temka [501]

Answer:

129.168

Step-by-step explanation:

multiply- 140.40*0.08=11.232

subtract- 140.40-11.232= 129.168

8 0
4 years ago
What is the solution to the equation StartFraction 3 Over m + 3 EndFraction minus StartFraction m Over 3 minus m EndFraction = S
Oksanka [162]

Answer:

No solution.

Step-by-step explanation:

Given fraction is:

\dfrac{3}{m+3} -\dfrac{m}{3-m} = \dfrac{m^2+9}{m^2-9}\\\Rightarrow \dfrac{3}{m+3} +\dfrac{m}{m-3} = \dfrac{m^2+9}{m^2-9}\\\Rightarrow \dfrac{3\times (m-3)+ m(m+3)}{(m+3)(m-3)}  = \dfrac{m^2+9}{m^2-9}\\\Rightarrow \dfrac{3 m-9+ m^2+3m}{m^2-9}  = \dfrac{m^2+9}{m^2-9}\\\Rightarrow \dfrac{m^2-9+ 6m}{m^2-9}  = \dfrac{m^2+9}{m^2-9}\\If\ m^2-9 \neq 0\ or\ m \neq 3\\\Rightarrow m^2-9+ 6m  = m^2+9\\\Rightarrow 6m = 18\\\Rightarrow m = 3

<u>Formula used:</u>

<u></u>(a+b)(a-b) = a^{2} -b^{2}<u></u>

<u></u>

But, the above equation was solved at the condition that:

m\neq 3

So, there is no solution for the given equation.

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3 years ago
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