<span>For given hyperbola:
center: (0,0)
a=7 (distance from center to vertices)
a^2=49
c=9 (distance from center to vertices)
c^2=81
c^2=a^2+b^2
b^2=c^2-a^2=81-49=32
Equation of given hyperbola:
..
2: vertices (0,+/-3) foci (0,+/-6)
hyperbola has a vertical transverse axis
Its standard form of equation: , (h,k)=(x,y) coordinates of center
For given hyperbola:
center: (0,0)
a=3 (distance from center to vertices)
a^2=9
c=6 (distance from center to vertices)
c^2=36 a^2+b^2
b^2=c^2-a^2=36-9=25
Equation of given hyperbola:
</span>
Answer:
13 units
Step-by-step explanation:
D is at (1,6) and C is at (-4,-6)
The distance is found by
d = sqrt(( y2-y1)^2+ (x2-x1)^2))
= sqrt( ( -6-6)^2 + (-4-1)^2)
= sqrt( -12^2 + -5^2)
= sqrt( 144+ 25)
= sqrt( 169)
= 13
Answer: 720
Step-by-step explanation:do 120 plus 120 plus 120 plus 120 plus 120 plus 120
Each food bank would receive 264 cans.
44 Bins with 24 cans. 44•24= 1,056
n= (44•24) / 4
n= 1,056 / 4
n= 264 cans per food bank
