Given
MINING A mine produces 42.5 tons of coal per hour.
Find out the how much coal will the mine produce in 9.5 hours.
To proof
As given in the question
A mine produces 42.5 tons of coal per hour i.e in the 1 hour mine produces the 42.5 tons .
Let us assume that the coal produce in the 9.5 hours be x.
than the equation becomes
x = 9.5 × 42.5
x = 403 . 75 tons
403 . 75 tons coal will the mine produces in the 9.5 hours.
Hence proved
10 1/6 just add the fractions together
240 sec + 45 sec= 285 sec
So you've got:
6.4x + 2.8y = 44.4
You want to know the value of (y) when x=3:
6.4 * 3 + 2.8y = 44.4
(6+0.4) * 3 + 2.8y = 44.4
18 + 1.2 + 2.8y = 44.4
19.2 + 2.8y = 44.4
2.8y= 44.4 - 19.2
2.8y = 25.2
y=(25.2)/(2.8)
y=9
This would be a rise over run solution, which means the answer would be -1400/8000, when simplified this equals -40/7, a.
