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Kaylis [27]
3 years ago
15

Given directed line segment AB determine point X on the graph such that X partions the segment A to B in a ratio of 1:4 and give

n its coordinates A(5,1) and b(-5,4)
(NEED THIS ASAP!!)
Mathematics
1 answer:
Viktor [21]3 years ago
8 0

Answer:

The coordinates of point X that divides the line in 1:4 are: (3,8/5)

Step-by-step explanation:

When a point divides a line with coordinates (x1,y1) and (x2,y2) in ratio m:n,

the coordinates of point are given by:

(x,y) = (\frac{mx_2+nx_1}{m+n} , \frac{my_2+ny_1}{m+n})

Given points are:

(x1,y1) = (5,1)

(x2,y2) = (-5,4)

Putting the values in the formula

X(x,y) = (\frac{(1)(-5)+(4)(5)}{1+4} , \frac{(1)(4)+(4)(1)}{1+4})\\= (\frac{-5+20}{5}, \frac{4+4}{5})\\=(\frac{15}{5}, \frac{8}{5})\\=(3,\frac{8}{5})

Hence,

The coordinates of point X that divides the line in 1:4 are: (3,8/5)

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What is the slope of the line that passes through the points (-9, -7) and<br> (-11, 6)
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Step-by-step explanation:

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1/4 (-12+3) -8/3<br> Simplified
labwork [276]

Answer:

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Step-by-step explanation:

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2 years ago
(ab^2 x -b^4a^3)^2<br><br> What is the answers
Umnica [9.8K]

Answer:

\left(ab^2x-b^4a^3\right)^2:\quad a^2b^4x^2-2a^4b^6x+a^6b^8

Step-by-step explanation:

Given the expression

\left(ab^2\:x\:-b^4a^3\right)^2

solving the expression

\left(ab^2\:x\:-b^4a^3\right)^2

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a=ab^2x,\:\:b=b^4a^3

so the expression becomes

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=a^2b^4x^2-2a^4b^6x+a^6b^8

Thus,

\left(ab^2x-b^4a^3\right)^2:\quad a^2b^4x^2-2a^4b^6x+a^6b^8

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