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3 years ago

Y=3x−4 y=−12x+3 solution solve by graphing

Mathematics

1 answer:

Anna11 [10]3 years ago

7 0

Answer:

(7/15,−13/5)

Equation Form:

x=7/15,y=−13/5

Step-by-step explanation:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

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The nutty professor sells cashews for 7.20 per pound snd brazil nuts flr 4.00 per pound. How much of each type should be used to

lutik1710 [3]

Answer:

<u>19.01 pound</u> of cashews and <u>16.99 pounds</u> of brazil nuts should be used to make a 36 pound mixture that sells for 5.69 per pound.

Step-by-step explanation:

Given:

The nutty professor sells cashews for 7.20 per pound and brazil nuts for 4.00 per pound.

Now, to find each type should be used to make a 36 pound mixture that sells for 5.69 per pound.

Let the quantity of cashews be $x.$

Let the quantity of brazil nuts be $y.$

So, total pound of mixture of nuts:

$x+y=36\\y=36-x\ \ \ .....(1)$

Now, the total price of mixture per pound:

$7.20(x)+4.00(y)=5.69(36)$

$7.2x+4y=204.84$

Substituting the value of $y$ from equation (1) we get:

$7.2x+4(36-x)=204.84$

$7.2x+144-4x=204.84$

$3.2x+144=204.84$

Subtracting both sides by 144 we get:

$3.2x=60.84$

Dividing both sides by 3.2 we get:

$x=19.01.$

The quantity of cashews = 19.01 pound.

Now, substituting the value of $x$ in equation (1) we get:

$y=36-x\\y=36-19.01\\y=16.99.$

The quantity of brazil nuts = 16.99 pounds.

Therefore, 19.01 pound of cashews and 16.99 pounds of brazil nuts should be used to make a 36 pound mixture that sells for 5.69 per pound.

7 0

4 years ago

It's a quartile question.

Mkey [24]

Answer:

D. 8

Step-by-step explanation:

the upper quartile = 8

5 0

3 years ago

2. The student council at Camp Creek Middle School determines that 3 out of 4

Gemiola [76]

Answer:

Hi there!

Your answer is:

996 students were apart of this survey!

Step-by-step explanation:

3 out of 4 students means that 75% of students prefer the assemblies be held on Friday.

If 75% = 747 students then:

/75

1% = 9.96 students

×100

100% = 996 students

I hope this makes sense!

8 0

3 years ago

Find the volume of the tetrahedron in the first octant bounded by the coordinate planes and the plane passing through (2 comma 0

SVETLANKA909090 [29]

Answer:

The volume of the tetrahedron is:

$\frac{50}{3}=16.667$

Step-by-step explanation:

The volume of the tetrahedron is given by the intersection of the planes x = 0, y = 0, z = 0 and the plane formed by the three points given.

The equation of the plane formed by the three points is:

Points: (2,0,0);(0,5,0);(0,0,4)

$\pi :\frac{x}{2} +\frac{y}{5} +\frac{z}{4} =1$

It can also be expressed as:

$10x + 4y+5z=20$

We have to calculate the triple integral, therefore we must define the domain:

The values of x are given by:

0≤x≤2

We will integrate the values of y between the y = 0 axis and the line formed when z = 0:

z=0 ⇒ 10x + 4y=2 ⇒ $y=\frac{20-10x}{4} =$

$0\leq y \leq 5-\frac{5}{2}x$

We will integrate the values of z between the plane z = 0 and the plane 10x + 4y+5z=20

10x + 4y+5z=20 ⇒ $z=\frac{20-10x-4y}{5} =4-2x-\frac{4}{5}y$

$0\leq z \leq 4-2x-\frac{4}{5}y$

The volume of the tetrahedron is:

$\int\limits^{2}_{0} \ \ \ \int\limits^{5-\frac{5}{2} x}_{0} \ \ \ \int\limits^{4-2x-\frac{4}{5}y }_{0} {z} \, dz\, dy \,dx$

$\int\limits^{2}_{0} \ \ \ \int\limits^{5-\frac{5}{2} x}_{0} \frac{z^2}{2}|^{4-2x-\frac{4}{5}y}_0\, dy \,dx$

$\frac{z^2}{2}|^{z=4-2x-\frac{4}{5}y}_{z=0}=\frac{5}{25}(5x+2(y-5))^2$

$\int\limits^{2}_{0} \ \ \ \int\limits^{5-\frac{5}{2} x}_{0} {\frac{5}{25}(5x+2(y-5))^2}\, dy \,dx$

$\int\limits^{2}_{0} {-\frac{25}{6}(x-2)^3} dx=-\frac{25}{24} (x-2)^4|^{2}_{0}=\frac{50}{3}$

6 0

4 years ago

What is the formula of Cosec (A+B)=

eimsori [14]

Answer:

Step-by-step explanation:

because it's A.B

C.D.

3 0

3 years ago