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hichkok12 [17]
2 years ago
5

Y=3x−4 y=−12x+3 solution solve by graphing

Mathematics
1 answer:
Anna11 [10]2 years ago
7 0

Answer:

(7/15,−13/5)

Equation Form:

x=7/15,y=−13/5

Step-by-step explanation:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

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Please help me please help help me help please
notsponge [240]

Answer:

An equation of a line is written in the form y=mx+b. ”m” is the slope and ”b” is the y-intercept. So, substituting the values, the equation is y=-4x+1.

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7 0
3 years ago
Debbie is 5 years older than
vovikov84 [41]

Answer:

Susan is 3 years  and Debbie is 8 years old. after 2 years Susan will be 5 Years and Debbie will be 10 years old

Step-by-step explanation:

let the present age of Susan be x years then Debbie is x+5 years

in 2 years

x +2 = x+5+2/2

x+2=x+7/2

2x +4 = x+7

x=3

6 0
3 years ago
I need help with this please :)
Marina CMI [18]

9514 1404 393

Answer:

  all are Not Equivalent

Step-by-step explanation:

The coefficient of t³ in the target expression is -3. In order for that to be the result of simplifying any of the given expressions, they must have ( )^(t^3) in the denominator. None do, so none of the offered choices is equivalent to the given expression.

_____

The expressions simplify like this:

  \dfrac{(2^3)^{t^3}}{2^{5t}}=2^{3t^3-5t}\\\\\dfrac{8^{t^3}}{32^t}=2^{3t^3-5t}\\\\8^{t^3}\cdot32^t=2^{3t^3+5t}

4 0
2 years ago
Solve for m.<br><br> 4+|7−m|=5
Stolb23 [73]
|7 - m| = 1
|7 - 6|

m = 6

hope this helps
5 0
3 years ago
Read 2 more answers
Which of these four sets of side lengths will form a right triangle? Set 1 4 cm, 5 cm, 6 cm Set 2 8 in., 12 in., 20 in. Set 3 10
Alenkasestr [34]

Answer:  The correct option is (D) SET 4.

Step-by-step explanation:  We are to select the correct set of side lengths that will form a right-angled triangle.

To form a right-angled triangle, we must have the following relation:

<em>Perpendicular² + Base² = Hypotenuse².</em>

<em>Hypotenuse is the length of the largest side; perpendicular and base are the two legs of the triangle.</em>

SET 1 :  14 cm, 5 cm, 6 cm.  

We have

5^2+6^2=25+36=61,\\\\14^2=196.

Therefore,

<em>Perpendicular² + Base² ≠ Hypotenuse².</em>

So, this set will not form a right-angled triangle.

SET 2 :  8 in., 12 in., 20 in.  

We have

8^2+12^2=64+144=208,\\\\20^2=400.

Therefore,

<em>Perpendicular² + Base² ≠ Hypotenuse².</em>

So, this set will not form a right-angled triangle.

SET 3 :  10 mm, 20 mm, 30 mm.  

We have

10^2+20^2=100+400=500,\\\\30^2=900.

Therefore,

<em>Perpendicular² + Base² ≠ Hypotenuse².</em>

So, this set will not form a right-angled triangle.

SET 4 :  12 ft, 16 ft, 20 ft.  

We have

12^2+16^2=144+256=400,\\\\20^2=400.

Therefore,

<em>Perpendicular² + Base² = Hypotenuse².</em>

So, this set will form a right-angled triangle.

Thus, the SET 4 will form a right-angles triangle.

Option (D) is correct.

5 0
3 years ago
Read 2 more answers
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