Can somebody pleaseee draw the line on these
1 answer:
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Answer: Option 'e' is correct.
Step-by-step explanation:
Since we have given that
Number of letters of the alphabet = 26
Number of letters in code :
One letter code, or two letter code, or three - letter code.
Since repetition of letters are allowed, then
if it is one letter code, the number of arrangement would be 26.
If it is two letter code, the number of arrangements would be
If it is three letter code, the number of arrangements would be
So, Number of different stocks to uniquely designate with these codes would be
Hence, Option 'e' is correct.
Y=kx+b
line is perpendicular y=1/3x+6⇒ k=-
=-3
so line y=-3x+a
this line that passes through (-9,12)⇔x=-9, y=12, so 12=-3(-9)+a
12=27+a
a=12-27
a=-15
y=-3x-15
P.s.picture<span> to test solutions <span>in the application</span></span>
line is perpendicular y=1/3x+6⇒ k=-
so line y=-3x+a
this line that passes through (-9,12)⇔x=-9, y=12, so 12=-3(-9)+a
12=27+a
a=12-27
a=-15
y=-3x-15
P.s.picture<span> to test solutions <span>in the application</span></span>
Answer:
and
Step-by-step explanation:
(a)
A = × 4
×
= 2 ×
= ×
← rationalise the denominator
= units²
(b)
Using Pythagoras' identity in the right triangle
let hypotenuse be h , then
h² = (4 )² + (
)²
= 32 +
= +
= ( take the square root of both sides )
h = =
×
← rationalise the denominator
h =