Question

In △ABD, altitude AC¯¯¯¯¯ intersects the right angle of triangle ABD at vertex A. BC=3.1 in. and CD=7.2 in..

Answer 1

Answer:

4.72

Step-by-step explanation:

I took the test.

Answer 2

Answer:

4.72 in.

Step-by-step explanation:

BC = 3.1 in.

CD = 7.2 in.

Altitude of right triangle altitude is given as $h = \sqrt{xy}$, where:

h = altitude

x = 3.1 in.

y = 7.2 in.

Plug in the values into the formula

$h = \sqrt{3.1*7.2}$

$h = \sqrt{22.32}$

$h = 4.72 in.$ (nearest hundred)