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2 years ago

14

Carol buys last years best selling novel, in hardcover, for $20.70. This is with a 10% discount from the original price. What wa

s the original price of the novel ?

1 answer:

N76 [4]2 years ago

7 0

The original price was $23. I found this by multiplying 23 x 0.9

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anastassius [24]

Answer:

Step-by-step explanation:

The answer is 12 miles, if every inch is 3 miles on the map then 3x4=12.

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3 years ago

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What the result of √[(-2a)^ 2]

Tanya [424]

If you take the square root of a number squared number then they cancel each other out and the number stays the same i.e. √[(4)^2] would equal 4.

In this problem the square root and numbered squared cancel out to leave the problem as -2a.

The solution of this problem is -2a

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3 years ago

Travelers who fail to cancel their hotel reservations when they have no intention of showing up are commonly referred to as no-s

notsponge [240]

Answer:

a) 0.0523 = 5.23% probability that at least two of the four selected will turn to be no-shows.

b) 0 is the most likely value for X.

Step-by-step explanation:

For each traveler who made a reservation, there are only two possible outcomes. Either they show up, or they do not. The probability of a traveler showing up is independent of other travelers. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

No-show rate of 10%.

This means that $p = 0.1$

Four travelers who have made hotel reservations in this study.

This means that $n = 4$

a) What is the probability that at least two of the four selected will turn to be no-shows?

This is $P(X \geq 2) = P(X = 2) + P(X = 3) + P(X = 4)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{4,2}.(0.1)^{2}.(0.9)^{2} = 0.0486$

$P(X = 3) = C_{4,3}.(0.1)^{3}.(0.9)^{1} = 0.0036$

$P(X = 4) = C_{4,4}.(0.1)^{4}.(0.9)^{0} = 0.0001$

$P(X \geq 2) = P(X = 2) + P(X = 3) + P(X = 4) = 0.0486 + 0.0036 + 0.0001 = 0.0523$

0.0523 = 5.23% probability that at least two of the four selected will turn to be no-shows.

b) What is the most likely value for X?

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{4,0}.(0.1)^{0}.(0.9)^{4} = 0.6561$

$P(X = 1) = C_{4,1}.(0.1)^{1}.(0.9)^{3} = 0.2916$

$P(X = 2) = C_{4,2}.(0.1)^{2}.(0.9)^{2} = 0.0486$

$P(X = 3) = C_{4,3}.(0.1)^{3}.(0.9)^{1} = 0.0036$

$P(X = 4) = C_{4,4}.(0.1)^{4}.(0.9)^{0} = 0.0001$

X = 0 has the highest probability, which means that 0 is the most likely value for X.

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2 years ago

Mai and Priya were on scooters. Mai traveled 15 meters in 6 seconds. Priya travels 22 meters in 10 seconds. Who was moving faste

Andrews [41]

Answer:

Mai was moving faster.

As, she covered a greater distance in the same amount of time.

Step-by-step explanation:

Given: Mai traveled 15 meters in 6 seconds and Priya travels 22 meters in 10 second.

Calculate the speed of both;

Speed defined as the rate at which an object covers distance.

$Speed = \frac{Distance}{Time}$

Mai traveled 15 meters in 6 seconds

then;

Speed = $\frac{15}{6} = 2.5 m/s$

Priya travels 22 meters in 10 second.

then;

Speed = $\frac{22}{10} = 2.2 m/s$

Reason: Mai traveled faster because she covered a greater distance in the same amount of time.

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2 years ago

Please answer fast please

juin [17]

#1:

A,B,C,E

#2:

12 edges, 12 vertices

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3 years ago

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