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3 years ago

Two consecutive odd numbers total 32. Find the smaller.

Mathematics

1 answer:

LuckyWell [14K]3 years ago

7 0

Answer:

Step-by-step explanation:

If you divide 32 by 2 you will get 16, therefore if you take the number before 16 and the number after 16 and add them together they will still equal 32. 15 + 17 = 32. The smaller number is 15.

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What is the inequality

RideAnS [48]

Is what is an inequality your question? An inequality is basically expressions that use the "greater than", "less than", "greater than or equal to", or "less than or equal to" symbols. A.K.A these: > < ≥ ≤

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3 years ago

Find the midpoint of CD if C(0, 3) and D(4,7).

Alecsey [184]

This midpoint should be (2,5)
Hope this helps

7 0

2 years ago

Read 2 more answers

What is the solution to the equation 3(2x+5)=3x+4x A.x=0 B.x=4 C.x=5 D.x=15

Ivan

x=15 and i have to write some more for 20 letters

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3 years ago

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A contractor purchases a shipment of 100 transistors. It is his policy to test 10 of these transistors and to keep the shipment

Serjik [45]

Answer:

Hence the probability of the at least 9 of 10 in working condition is 0.3630492

Step-by-step explanation:

Given:

total transistors=100

defective=20

To Find:

P(X≥9)=P(X=9)+P(X=10)

Solution:

There are 20 defective and 80 working transistors.

Probability of at least 9 of 10 should be working out 80 working transistors

is given by,

P(X≥9)=P(X=9)+P(X=10)

{80C9 gives set of working transistor and 20C1 gives 20 defective transistor and 100C10 is combination of shipment of 10 transistors}

P(X≥9)= ${80C9*20C(10-9)}/(100C10)+{80C10*20(10-10)}/(100C10)$

(Use the permutation and combination calculator)

P(X≥9)=(231900297200*20/17310309456440)

+(1646492110120/17310309456440)

P(X≥9)=0.267933+0.0951162

P(X≥9)=0.3630492

4 0

3 years ago

Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. Write the polynomial in s

wolverine [178]

Answer:

x^4 - 14x^2 - 40x - 75.

Step-by-step explanation:

As complex roots exist in conjugate pairs the other zero is -1 - 2i.

So in factor form we have the polynomial function:

(x - 5)(x + 3)(x - (-1 + 2i))(x - (-1 - 2i)

= (x - 5)(x + 3)( x + 1 - 2i)(x +1 + 2i)

The first 2 factors = x^2 - 2x - 15 and

( x + 1 - 2i)(x +1 + 2i) = x^2 + x + 2ix + x + 1 + 2i - 2ix - 2i - 4 i^2

= x^2 + 2x + 1 + 4

= x^2 + 2x + 5.

So in standard form we have:

(x^2 - 2x - 15 )(x^2 + 2x + 5)

= x^4 + 2x^3 + 5x^2 - 2x^3 - 4x^2 - 10x - 15x^2 - 30x - 75

= x^4 - 14x^2 - 40x - 75.

7 0

3 years ago