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3 years ago

B = 2c + 6 what is the function?

Mathematics

2 answers:

Leya [2.2K]3 years ago

7 0

Answer:

2c put me as brainlest

Step-by-step explanation:

Let's solve for c.

b=2c+6

Step 1: Flip the equation.

2c+6=b

Step 2: Add -6 to both sides.

2c+6+−6=b+−6

2c=b−6

Step 3: Divide both sides by 2.

b−6

b−3

Answer:

b−3

now if ur just looking for the funtipn the asnwer would be 2c i think

earnstyle [38]3 years ago

3 0

Answer:

B. -6+8d-2c C. -2c+8d-6

Step-by-step explanation:

In order to determine which expressions are equivalent to you need to set the expression equal to the options available.

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3 years ago

Find an equation of the sphere with point P such that the distance from P to A(−2, 6, 2) is twice the distance from P to B(4, 3,

Sveta_85 [38]

Answer:

$3*x^{2} - 36*x + 3*y^{2} -12*y + 3*z^{2} -4*z + 62 = 0$

Step-by-step explanation:

The distance from a point $P = (x,y,z)$ to another point $A = (a,b,c)$ is given by $((x-a)^{2} + (y-b)^{2} + (z-c)^{2})^{1/2}$ .

So, if the distance from P to A is twice the distance from P to B, we have an equality given by:

$((x+2)^{2} + (y-6)^{2} + (z-2)^{2})^{1/2} = 2*((x-4)^{2} + (y-3)^{2} + (z+1)^{2})^{1/2}$

If we power by 2 both sides of the equality to remove the square roots, we have:

$(x+2)^{2} + (y-6)^{2} + (z-2)^{2} = 4 * ((x-4)^{2} + (y-3)^{2} + (z+1)^{2})$

And solving every parenthesis and operating the similar terms, we have:

$(x^{2} + 4*x + 2) - 4*(x^{2} - 8*x + 16) + (y^{2} - 12 * y + 36) - 4*(y^{2} -6*y + 9) + (z^{2} -4*z+4) - 4*(z^{2}+2*z+1) = 0$

Operating and multiplying both sides by -1:

$(3*x^{2} - 36*x +62) + (3*y^{2} -12*y + 0) + (3*z^{2} -4*z + 0) = 0$

Giving as result:

$3*x^{2} - 36*x + 3*y^{2} -12*y + 3*z^{2} -4*z + 62 = 0$

The sphere can be seen here: https://www.wolframalpha.com/input/?i=3*x%5E2+-+36*x+%2B+3*y%5E2+-12*y+%2B+3*z%5E2+-4*z+%2B+62+%3D+0

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Answer:

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Step-by-step explanation:

Solve for x by simplifying both sides of the equation, then isolating the variable.

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