Answer:
D) arccsc (x) = arcsin (1/x)
Step-by-step explanation:
Here's how you can prove it: Consider a right triangle with hypotenuse 1 and a side length 1/x. If θ is the angle opposite of 1/x, then:
sin θ = 1/x
and
csc θ = x
Solving for θ:
θ = arcsin (1/x)
θ = arccsc (x)
Therefore:
arccsc (x) = arcsin (1/x)
What we have so far:
INITIAL CASH AMOUNT IN THE BANK: USD3,000
ANNUAL INCREASE OF THE CASH AMOUNT IN THE BANK: 10%
YEARS THE CASH STAYED IN THE BANK: 2 years.
AMOUNT WITHDRAWN AT THE END OF YEAR 1: USD1,206
AMOUNT WITHDRAWN AT THE END OF YEAR 2: USD1,206
First, we need to solve for YEAR 1:
FOR YEAR 1:
Initial Deposit * Annual Increase Rate = Annual Increase
3,000 * 0.10 = Year 1's Annual Increase
Year 1's Annual Increase = USD300
∴The YEAR 1'S ANNUAL INCREASE IS USD300.
∴The NEW AMOUNT is now USD3,300.
BUT NOT SO FAST! After the year, you took out USD1,206.
New Amount - USD1,206 = Year 1 Amount
3,300 - 1,206 = Year 1 Amount
Year 1 Amount = USD2094
∴The YEAR 1 AMOUNT which will carry over to YEAR 2 is USD2094.
Now, let us solve for the REMAINING BALANCE.
FOR YEAR 2's Annual Increase:
YEAR 1 AMOUNT * Annual Increase = Year 2's Annual Increase
2094*0.10 = Year 2's Annual Increase
Year 2's Annual Increase = USD209.4
∴The YEAR 1'S ANNUAL INCREASE IS USD209.4.
∴The NEW AMOUNT is now USD2,303.4.
But you took out USD1,206
USD2,303.4 - USD1,206 = Remaining Balance
Remaining Balance = USD1097.4
∴The Answer is: USD1097.4
Answer:
f(11) = 9
Step-by-step explanation:
f(x) = 1/4(5-x)^2
f(x) = 1/4 (5-11) ^2
f(11) = 1.25 - 2.75 ^2
f(11) = 9
Its length would be 9 ft so 9 x 8 is 72.
I think it’s always because the absolute value is always positive.
