Answer:
see below
Step-by-step explanation:
Option 1: the two solution sets overlap at <em>x=1</em>.
Option 2: the two solution sets do not overlap; no solution.
Option 3: together, the two set describe <em>all real numbers</em>.
Answer:
If I am correct It is Commutative Property
Hope That Helps!
Answer:
what's the question ?
Step-by-step explanation:
Up to multiples, if you're given the roots you can write the polynomial by multiplying several parenthesis in the form
![(x-x_0)](https://tex.z-dn.net/?f=%28x-x_0%29)
where
is a root. So, in your case, you have
![f(x) = a(x+6)(x+5)(x+1)](https://tex.z-dn.net/?f=f%28x%29%20%3D%20a%28x%2B6%29%28x%2B5%29%28x%2B1%29)
We can fix the parameter a by imposing f(0)=60:
![f(0)=a(0+6)(0+5)(0+1)=30a=60\iff a=2](https://tex.z-dn.net/?f=f%280%29%3Da%280%2B6%29%280%2B5%29%280%2B1%29%3D30a%3D60%5Ciff%20a%3D2)
So, your polynomial is
![f(x) = 2(x+6)(x+5)(x+1)=2x^3+24x^2+82x+60](https://tex.z-dn.net/?f=f%28x%29%20%3D%202%28x%2B6%29%28x%2B5%29%28x%2B1%29%3D2x%5E3%2B24x%5E2%2B82x%2B60)
Answer:
C = 10
Step-by-step explanation:
+
= ![C^{2}](https://tex.z-dn.net/?f=C%5E%7B2%7D)
+
= 100
= 10