Answer: D 3<x<infinity
Step-by-step explanation:
Cos θ = adjacent / hypothenus = 5/13
opposite = sqrt(hypothenus^2 - adjacent^2) = sqrt(13^2 - 5^2) = sqrt(169 - 25) = sqrt(144) = 12
sec θ = 1/cos θ = 1/(adjacent / hypothenus) = hypothenus / adjacent = 13/5
cot θ = 1/tan θ = 1/(opposite/adjacent) = adjacent / opposite = 5/12
sec θ = 13/5
cot θ = 5/12
Answer:
(n+5)² - (n+3)² =
= (n² + 10n + 25) - (n² + 6n + 9)
= n² + 10n + 25 - n² - 6n - 9
= 4n + 16
= 4(n + 4) ⋮ 4
The answer would be (8pi +12) in^2
This is because to solve for the semicircle the equation is:
1/2*pi*r^2 1/2*pi*16
And the equation for the triangle is:
1/2*hb*h 1/2*8*3
(Plz mark Brainliest have a nice day)
