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Anestetic [448]
4 years ago
9

Simplify the square root of -16 + the square root of -9

Mathematics
1 answer:
matrenka [14]4 years ago
6 0

Answer:

7i

Step-by-step explanation:

See attached image.

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Yesterday 160 guest at a hotel called for room service, and 240 guest did not called for room service. What is the percentage of
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160/400
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8 0
3 years ago
Hello, a quick question which number is least to greatest 0.359, 0.35, 1
Aleksandr-060686 [28]

Answer:

0.35, 0.359, 1

Step-by-step explanation:

0.359 = 359 thousandths

0.35 = 0.350 = 350 thousandths

1 = 1.000 = 1000 thousandths

Since 350 < 359 < 1000, then from least to greatest you get

0.35, 0.359, 1

6 0
4 years ago
A) 5(3z-2)=-16-3(2z+5) <br> b) 5(2 –3k) + (3k –2) = -4
FinnZ [79.3K]
The answers is
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4 0
3 years ago
45.7 kilometers =<br> meters
VashaNatasha [74]

Answer:

45.7 kilometers = 45,700 meters

Explanation:

Hi!
Okay, so basically, in one kilometer, there are 1000 meters.
Using this problem, all you have to do is <u>multiply 45.7 by 1000</u>, which is 45,700.

Whatever value is used for kilometers (ex. 2), just multiply by 1000, and you’ll get the value as meters (ex. 2 x 1000 = 2000 meters).


Hope this helps!

8 0
2 years ago
Read 2 more answers
What is the solution for x in the given equation? The square root of 9x +7 + the square root of 2x = 7
cestrela7 [59]

Answer:

The solution is x =2 for the given equation \sqrt{9x+7} +\sqrt{2x}=7

Step-by-step explanation:

We need to find the solution for x in the given equation.

\sqrt{9x+7} +\sqrt{2x}=7

Solving:

Subtract \sqrt{2x} from both sides

\sqrt{9x+7} =7-\sqrt{2x}

Taking square on both sides

(\sqrt{9x+7})^2 =(7-\sqrt{2x})^2\\Using\,\, (a-b)^2 = a^2-2ab-b^2\\9x+7=(7)^2-2(7)(\sqrt{2x})+(\sqrt{2x})^2\\9x+7=49-14\sqrt{2x}+2x\\9x-2x+7-49=-14\sqrt{2x}\\7x-42=-14\sqrt{2x}\\Taking\,\,square\,\,on\,\,both\,\,sides\\(7x-42)^2=(-14\sqrt{2x})^2\\49x^2-2(7x)(42)+(42)^2= 196(2x)\\49x^2-588x+1764=392x\\49x^2-588x+1764-392x=0\\49x^2-980x+1764=0\\Using \,\,quadratic \,\, equation  \,\,to \,\, find \,\, value \,\, of \,\, x \\x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\a= 49, \, b= -980 \,\,and\,\, c = 1764

Putting values and solving

x=\frac{-(-980)\pm\sqrt{(-980)^2-4(49)(1760)}}{2(49)}\\x=\frac{980\pm\sqrt{614656}}{98}\\Solving\\x=18 \,\, and x =2

Verifying the solution by putting values of x in given equation

Putting x=18

\sqrt{9x+7} +\sqrt{2x}=7\\\sqrt{9(18)+7} +\sqrt{2(18)}=7\\\sqrt{169} +\sqrt{36}=7\\13+6=7\\19\neq 7

So, x=18 is not solution o given equation.

Putting x = 2

\sqrt{9x+7} +\sqrt{2x}=7\\\sqrt{9(2)+7} +\sqrt{2(2)}=7\\\sqrt{25} +\sqrt{4}=7\\5+2=7\\7=7

So, x=2 satisfies the equation

The solution is x =2 for the given equation \sqrt{9x+7} +\sqrt{2x}=7

7 0
3 years ago
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