Try this:
1. sum of numbers is x+y=67, the difference between them is x-y=11
2. it is possible to make up and resolve the system:
I'd say the answer is 5 wins
hope this helps
We have a domain of a function, that is, which x-es can we throw in. But we are asking which y-s will we get given that we can only throw x-es in
.
Let's try
even though we are forbidden to put 4 inside
we are still able to do so.
So
what we just got is the upper limit of the range. The lower limit is
.
So the range is just
.
Hope this helps :)
Answer: 
Step-by-step explanation:
Given
The inequality is 
adding both side 7

Multiply both sides by 

the shaded region in the figure indicates the solution set.