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3 years ago

13

Math Exit Slip: Value-Mart is having a back -to - school sale on pencils. A pack of of 20 sells for $7.97, whereas a 12-pack cos

ts $4.77. Which is the better buy?

1 answer:

Whitepunk [10]3 years ago

4 0

Answer: The pack of 20.

Step-by-step explanation:

It is because a pack of 20 sells for 2.50 for each pencil, and the pack of 12 sells for 2.51 per pencil, so that means the pack of 20 is cheaper.

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The average of 25, 29, and x is 29. Find x.

Andrej [43]

X is going to equal 33. 25+29+x/3=33

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2 years ago

Read 2 more answers

Lapatulllka [165]

Answer:

f[g(4)] = 4

Step-by-step explanation:

Given table:

$\begin{array}{| c | c | c | c | c | c |}\cline{1-6} x & -6 & -4 & 1 & 3 & 4\\\cline{1-6} f(x) & 4 & -1 & -6 & 1 & 3 \\\cline{1-6} g(x) & 1 & 4 & 3 & -4 & -6 \\\cline{1-6}\end{array}$

f[g(4)] is a composite function.

When calculating <u>composite functions</u>, always work from inside the brackets out.

Begin with g(4): g(4) is the value of function g(x) when x = 4.

From inspection of the given table, g(4) = -6

Therefore, f[g(4)] = f(-6)

f(-6) is the value of function f(x) when x = -6.

From inspection of the given table, f(-6) = 4

Therefore, f[g(4)] = 4

3 0

1 year ago

Read 2 more answers

Which equation does not have the same solution as the others?

ladessa [460]

X/4 = 2.....x = 8
x - 9 = 17....x = 26 <=== there is the odd ball
x + 12 = 20....x = 8
2x = 16....x = 8

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2 years ago

I really had some trouble with this problem:( & I need some help

Natasha_Volkova [10]

The answers are in the photo

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1 year ago

A, b, c, d are the roots of 3x⁴-6x²+2=0. what is the value of a⁴+b⁴+c⁴+d⁴?

Pani-rosa [81]

Hello,

P(x)=x^4-6x²+2=(x-a)(x-b)(x-c)(x-d)
=x^4-(a+b+c+d)x^3+(ab+ac+ad+bc+bd+cd)x^2-(abc+abd+acd+bcd)x+abcd

==>
ab+ac+ad+bc+bd+cd=-6
abc+abd+acd+bcd=0
abcd=2
a+b+c+d=0 ==>(a+b+c+d)²=0=a²+b²+c²+d²+2(ab+ac+ac+bc+bd+cd)
==>a²+b²+c²+d²=0-2*(-6)=12

if a is a root P(a)=0==>a^4-6a²+2=0
if b is a root P(b)=0==>b^4-6b²+2=0
if c is a root P(a)=0==>c^4-6c²+2=0
if d is a root P(a)=0==>d^4-6d²+2=0

==>a^4+b^4+c^4+d^4-6(a²+b²+c²+d²)+4*2=0
==>a^4+b^4+c^4+d^4=-8+6*12=64

6 0

3 years ago