I NEED HELP PLEASE PLEASE

Mathematics

1 answer:

Aliun [14]3 years ago

5 0

Answer:

length= 17.5

width=11.5

( I worked this out myself but I don't know if its right tho)

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A historic museum charges a rental fee plus $2 per hour for an audio tour guide. The total cost for 4 hours is $12. Find and int

Serhud [2]

We can represent this problem with the following linear equation
y = 2x + 4
where
y: total cost
x: number of hours
the slope of the line is
m = 2
Which means that for every hour of audio tour guide they charge $ 2.
For "zero" hours (x = 0) a rental fee of $ 4 must be paid.

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4 years ago

The "cold start ignition time" of an automobile engine is being investigated by a gasoline manufacturer. The following times (in

Oliga [24]

Answer:

The boxplots are on the figure attached. And the explanation is below.

Step-by-step explanation:

For the first formulation we have the following dataset:

1.76, 1.84, 2.71, 2.26, 3.15, 3.21, 2.48, 1.87

We can construct a box plot with the following R code:

> x1<-c( 1.76, 1.84, 2.71, 2.26, 3.15, 3.21, 2.48, 1.87)

> boxplot(x1,main="Boxplot method 1")

For the scond formulation we have the following data:

1.75, 2.08, 3.17, 3.21, 2.74, 2.83, 3.47, 2.47, 1.98

And the boxplot can be constructed with the following R code:

> x2<-c(1.75, 2.08, 3.17, 3.21, 2.74, 2.83, 3.47, 2.47, 1.98)

> boxplot(x2,main="Boxplot method 2")

And we can get the comparative 5 number results for each case:

> summary(x1)

Min. 1st Qu. Median Mean 3rd Qu. Max.

1.760 1.863 2.370 2.410 2.820 3.210

> summary(x2)

Min. 1st Qu. Median Mean 3rd Qu. Max.

1.750 2.080 2.740 2.633 3.170 3.470

As we can see both histograms shows asymmetrical distributions. For the first method Mean>Median so then we can conclude that the distribution would be approximately skewed to the right. For the second case the Median>Mean so we can conclude that the distribution would be approximately skwewed to the left.