Question

The annual salaries of employees in a large company are approximately normally distributed with a mean of $50,000 and a standard deviation of $2000. What is the probability of randomly selecting one employee who earned less than or equal to $45,000

Answer 1

Answer:

The probability of randomly selecting one employee who earned less than or equal to $45,000=0.00621

Step-by-step explanation:

We are given that

Mean,$\mu=50000$

Standard deviation,$\sigma=2000$

We have to find the probability of randomly selecting one employee who earned less than or equal to $45,000.

$P(x\leq 45000)=P(\frac{x-\mu}{\sigma}\leq \frac{45000-50000}{2000})$

$P(x\leq 45000)=P(Z\leq-\frac{5000}{2000})$

$P(x\leq 45000)=P(Z\leq -2.5)$

$P(x\leq 45000)=0.00621$

Hence,  the probability of randomly selecting one employee who earned less than or equal to $45,000=0.00621