Using the normal distribution relation, the probability that sample will exceed the weight limit is 0.004
<u>Using the relation</u> ::
The mean, μ = np = (162 × 19) = 3078
The standard deviation, σ = 28 × √19 = 122.049
<u>The Zscore</u> :
Zscore = (3401 - 3078) ÷ (122.049)
Zscore = 2.65
Hence,
P(Z > 2.65) = 1 - P(Z < 2.65)
Using a normal distribution table :
P(Z > 2.65) = 1 - 0.9959
P(Z > 2.65) = 0.004
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The number of sugar cubes in the box is 180
<h3>How to determine the number of sugar cubes?</h3>
The given parameters are:
- Layers = 5
- Pieces = 2 or 3
- Cups of tea = 61 and 88
Multiply 61 and 88 by 2 and 3
61 * 2 = 122
61 * 3 = 183
88 * 2 = 176
88 * 3 = 264
The number of sugar cubes cannot be 122 and 264, because they are out of the range
So, we have:
183 and 176
There are 5 layers.
This means that the number of sugar cubes is divisible by 5.
The only number between 176 and 183 that is divisible by 5 is 180
Hence, the number of sugar cubes is 180
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Answer:
No solution
Step-by-step explanation:
3x + 6y =36
-3x - 6y =0
------------------add
0 ≠ 36
No solution
Ok, So:
10x3=30-3=27
It Would Be 27
They only have 1 common point
