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FrozenT [24]
3 years ago
9

The product of two complex numbers is (always, sometimes, never] a complex number

Mathematics
1 answer:
Shalnov [3]3 years ago
6 0

The product of two complex numbers is SOMETIMES a complex number.

this is because you can add 2 complex numbers and get a whole number, which is not a complex number. However, you can add 2 complex numbers and sometimes get another complex number.

May I have brainliest please? :)

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-5(x+7)&lt;-10<br> solve for x
olga2289 [7]
-5(x+7)<-10.
You need to use the distributive property.
-5x - 35 < -10.
You need to cancel out -35, so you add it to itself, & -10.
-5x < 25.
You need to divide -5 by itself & 25.
x>-5.
3 0
4 years ago
Read 2 more answers
Please help! I’ll mark as brainliest
Talja [164]

Answer:

see below

Step-by-step explanation:

domain is all x values for which a graph has
and range is all y values for which a graph has

domain in this case is -4<x<4. The range is -3<= x <= 3

Function is increasing when slope of the line is positive, function is decreasing when slope of the line is negative.

When 2 lines meet and there is an edge like at (-1,3) there is no increase of decrease of the function. If you are in calculus, this is because the derivative of the function will not be valid at those points. If you are not in calculus, then don't pay attention to the derivative stuff.

Function is increasing on interval -4<x<-1 and 2<x<4
Function is decreasing on interval -1<x<2

7 0
3 years ago
At one gym, there is a $12 start-up fee, and after that each month, m, at the gym costs $20. At another gym, each month at the g
nata0808 [166]

Answer:

6 months

Step-by-step explanation:

Gym1

12 + 20m

Gym2

22m

Set them equal

12 +20m = 22m

Subtract 20 m from each side

12 +20m-20m = 22m-20m

12 = 2m

Divide by 2

12/2 = 2m/2

6 =m

5 0
4 years ago
Set A of six numbers has a standard deviation of 3 and set B of four numbers has a standard deviation of 5. Both sets of numbers
Alenkinab [10]

Given:

\sigma_A=3

n_A=6

\sigma_B=5

n_B=4

\overline{x}_A=\overline{x}_B

To find:

The variance. of combined set.

Solution:

Formula for variance is

\sigma^2=\dfrac{\sum (x_i-\overline{x})^2}{n}      ...(i)

Using (i), we get

\sigma_A^2=\dfrac{\sum (x_i-\overline{x}_A)^2}{n_A}

(3)^2=\dfrac{\sum (x_i-\overline{x}_A)^2}{6}

9=\dfrac{\sum (x_i-\overline{x}_A)^2}{6}

54=\sum (x_i-\overline{x}_A)^2

Similarly,

\sigma_B^2=\dfrac{\sum (x_i-\overline{x}_B)^2}{n_B}

(5)^2=\dfrac{\sum (x_i-\overline{x}_B)^2}{4}

25=\dfrac{\sum (x_i-\overline{x}_B)^2}{4}

100=\sum (x_i-\overline{x}_B)^2

Now, after combining both sets, we get

\sigma^2=\dfrac{\sum (x_i-\overline{x}_A)^2+\sum (x_i-\overline{x}_B)^2}{n_A+n_B}

\sigma^2=\dfrac{54+100}{6+4}

\sigma^2=\dfrac{154}{10}

\sigma^2=15.4

Therefore, the variance of combined set is 15.4.

7 0
3 years ago
Three equivalent ratios of 10 to 15
wariber [46]
10/15 10 to 15 10:15 are answers
5 0
3 years ago
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