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Alex17521 [72]
3 years ago
5

How many ways can you arrange the letters in the word Vacuum?

Mathematics
2 answers:
Flura [38]3 years ago
7 0

Answer:

The answer is 360 ways

Step-by-step explanation:

Kazeer [188]3 years ago
4 0

Answer:

720 arrangements

So the six letters can be a combination of 6×5×4×3×2×1 letters or 720 arrangements.

Step-by-step explanation:

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Solve the simultaneous equation<br> 4x-y=9 <br> 2x-3y= -23
MrMuchimi

Answer:

x = 5

y = 11

Step-by-step explanation:

y = 4x - 9

2x -3(4x - 9) = -23

2x - 12x + 27 = -23

-10x = -23 -27

-10x = -50

minus cancels out

x = 5

y = 4(5) -9

y = 20 - 9

y = 11

4 0
3 years ago
Write 243 as a power of 3
Vlad [161]
Um... Maybe it's 6^3+3^3
5 0
3 years ago
PLEASEEEE!!! What is the best first step for solving the equation -1.8 = 2z−185
Vsevolod [243]

The first step in this equation is to Subtract 18 from both sides of the equation.

5 0
3 years ago
4. gr - 8 = 34x - 12<br> Which exponent property did you use to solve for x? (1 point)
gogolik [260]
Step by step:
GR-8 = 34x - 12
• move variable to left hand side
-34x + gr -8 = - 12
• change expression and move to right side
-34x = - 12 - gr - 8
• calculate sum
-34x = - 4 - gr
• divide both sides
X = 2/17 + 1/34gr
And there’s your answer :)
3 0
3 years ago
The distribution of weights for newborn babies is approximately normally distributed with a mean of 7.4 pounds and a standard de
blsea [12.9K]

Answer:

1. 15.87%

2.  6 pounds and 8.8 pounds.

3. 2.28%

4. 50% of newborn babies weigh more than 7.4 pounds.

5. 84%

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 7.4 pounds

Standard Deviation, σ = 0.7 pounds

We are given that the distribution of weights for newborn babies is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

1.Percent of newborn babies weigh more than 8.1 pounds

P(x > 8.1)

P( x > 8.1) = P( z > \displaystyle\frac{8.1 - 7.4}{0.7}) = P(z > 1)

= 1 - P(z \leq 1)

Calculation the value from standard normal z table, we have,  

P(x > 8.1) = 1 - 0.8413 = 0.1587 = 15.87\%

15.87% of newborn babies weigh more than 8.1 pounds.

2.The middle 95% of newborn babies weight

Empirical Formula:

  • Almost all the data lies within three standard deviation from the mean for a normally distributed data.
  • About 68% of data lies within one standard deviation from the mean.
  • About 95% of data lies within two standard deviations of the mean.
  • About 99.7% of data lies within three standard deviation of the mean.

Thus, from empirical formula 95% of newborn babies will lie between

\mu-2\sigma= 7.4-2(0.7) = 6\\\mu+2\sigma= 7.4+2(0.7)=8.8

95% of newborn babies will lie between 6 pounds and 8.8 pounds.

3. Percent of newborn babies weigh less than 6 pounds

P(x < 6)

P( x < 6) = P( z > \displaystyle\frac{6 - 7.4}{0.7}) = P(z < -2)

Calculation the value from standard normal z table, we have,  

P(x < 6) =0.0228 = 2.28\%

2.28% of newborn babies weigh less than 6 pounds.

4. 50% of newborn babies weigh more than pounds.

The normal distribution is symmetrical about mean. That is the mean value divide the data in exactly two parts.

Thus, approximately 50% of newborn babies weigh more than 7.4 pounds.

5. Percent of newborn babies weigh between 6.7 and 9.5 pounds

P(6.7 \leq x \leq 9.5)\\\\ = P(\displaystyle\frac{6.7 - 7.4}{0.7} \leq z \leq \displaystyle\frac{9.5-7.4}{0.7})\\\\ = P(-1 \leq z \leq 3)\\\\= P(z \leq 3) - P(z < -1)\\= 0.9987 -0.1587= 0.84 = 84\%

84% of newborn babies weigh between 6.7 and 9.5 pounds.

7 0
3 years ago
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