If f(x)=2x^6+x^5+32x+32, is (x+2) a factor of f(x).
2 answers:
Answer: By the factor theorem if (x + 2) is a factor of f(x) then f(- 2) = 0
f(- 2)
= 2(-2)^{6} + -2)^{5} + 32(- 2) + 32
= 2(64) - 32 - 64 + 32
= 128 - 32 - 64 + 32
= 64 ≠ 0
Hence (x + 2) is not a factor of f(x)
Answer:
No
Step-by-step explanation:
By the factor theorem if (x + 2) is a factor of f(x) then f(- 2) = 0
f(- 2)
= 2
+ 
+ 32(- 2) + 32
= 2(64) - 32 - 64 + 32
= 128 - 32 - 64 + 32
= 64 ≠ 0
Hence (x + 2) is not a factor of f(x)
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