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2 years ago

If f(x)=2x^6+x^5+32x+32, is (x+2) a factor of f(x).

Mathematics

2 answers:

Greeley [361]2 years ago

8 0

Answer: By the factor theorem if (x + 2) is a factor of f(x) then f(- 2) = 0

f(- 2)

= 2(-2)^{6} + -2)^{5} + 32(- 2) + 32

= 2(64) - 32 - 64 + 32

= 128 - 32 - 64 + 32

= 64 ≠ 0

Hence (x + 2) is not a factor of f(x)

Angelina_Jolie [31]2 years ago

4 0

Answer:

Step-by-step explanation:

By the factor theorem if (x + 2) is a factor of f(x) then f(- 2) = 0

f(- 2)

= 2 $(-2)^{6}$ + $-2)^{5}$ + 32(- 2) + 32

= 2(64) - 32 - 64 + 32

= 128 - 32 - 64 + 32

= 64 ≠ 0

Hence (x + 2) is not a factor of f(x)

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180-19=161

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3 years ago

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2 years ago

Using dimensional analysis, what unit of time will make the statement true?

frosja888 [35]

The unit of time that will make the statement true is "day"

<h3>What unit of time will make the statement true?</h3>

The conversion equation is given as:

Seconds + Seconds/? * day = seconds

Represent the blank with a variable (x)

So, we have:

Seconds + Seconds/x * day = seconds

Subtract "seconds" from both sides of the equation

So, we have:

Seconds/x * day = seconds

Divide both sides of the equation by "seconds"

So, we have:

1/x * day = 1

Multiply both sides by x

x= day

Hence, the unit of time that will make the statement true is "day"