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2 years ago

7k = 3k - 36 It’s gotta be a step by step equation

Mathematics

1 answer:

vovikov84 [41]2 years ago

8 0

K=-9 Bc you move the variable to the left and then collect like terms and divide both sides

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Complete each trinomial such that it can be rewritten in the form a(x+b)^2 or a(x-b)^2

scoundrel [369]

The value of the expression in the form a(x+b)^2 is 1.5(x+2)^2 - 4

<h3>Vertex Form of a quadratic expression</h3>

Given the quadratic expressions

1.5x^2+6x+......

1.5(x^2 + 4x)

Using the completing the square method

The coefficient of x = 4

Half of the coefficient = 4/2 = 2

The square of the result = 2^2 = 4

The equation is expressed as:

f(x) = 1.5(x^2+4x+ 4) - 4

f(x) = 1.5(x+2)^2 - 4

Hence the value of the expression in the form a(x+b)^2 is 1.5(x+2)^2 - 4

Learn more on completing the square method here: brainly.com/question/1596209

6 0

2 years ago

Пожалуйста,очень нужны 4,5,6<br> Срочнооооооо<br> Спасибо заранее

kifflom [539]

B. is the answer to your question!! Hope this helps!! :D

4 0

3 years ago

The Bishop family celebrated a birthday by dining out at a local restaurant. Their bill was $97.45. Mr. Bishop would like to lea

serg [7]

97.45 • 0.18 = 17.54. 97.45 + 17.54 = 114.99. I think this is right.

6 0

3 years ago

Read 2 more answers

Which expression is equivalent to 5(9 + 7)?<br><br> 14 + 12<br> 14 + 7<br> 45 + 7<br> 45 + 35

nika2105 [10]

5(9 + 7) = 5 x 9 + 5 x 7 = 45 + 35

3 0

3 years ago

A right circular cone is undergoing a transformation in such a way that the radius of the cone is increasing at a rate of 1/2 in

Ivenika [448]

Answer:

The volume is decreasing at the rate of 1.396 cubic inches per minute

Step-by-step explanation:

Given

Shape: Cone

$\frac{dr}{dt} =\frac{1}{2}$ --- rate of the radius

$\frac{dh}{dt} =-\frac{1}{3}$ --- rate of the height

$r = 2$

$h = \frac{1}{3}$

Required

Determine the rate of change of the cone volume

The volume of a cone is:

$V = \frac{\pi}{3}r^2h$

Differentiate with respect to time (t)

$\frac{dV}{dt} = \frac{\pi}{3}(2rh \frac{dr}{dt} + r^2 \frac{dh}{dt})$

Substitute values for the known variables

$\frac{dV}{dt} = \frac{\pi}{3}(2*2*\frac{1}{3}* \frac{1}{2} - 2^2 *\frac{1}{3})$

$\frac{dV}{dt} = \frac{\pi}{3}(\frac{4}{3}* \frac{1}{2} - \frac{4}{3})$

$\frac{dV}{dt} = \frac{\pi}{3}(\frac{4}{3}(\frac{1}{2} - 1))$

$\frac{dV}{dt} = \frac{\pi}{3}(\frac{4}{3}*- 1)$

$\frac{dV}{dt} = -\frac{\pi}{3}*\frac{4}{3}$

$\frac{dV}{dt} = -\frac{22}{7*3}*\frac{4}{3}$

$\frac{dV}{dt} = -\frac{22}{21}*\frac{4}{3}$

$\frac{dV}{dt} = -\frac{88}{63}$

$\frac{dV}{dt} =-1.396in^3/min$

The volume is decreasing at the rate of 1.396 cubic inches per minute

3 0

3 years ago