Answer:
we will fail to reject the null hypothesis and conclude that the mean pressure is not different from 4.7 psi
Step-by-step explanation:
Let's first define the hypothesis;
Null hypothesis: H0: μ = 4.7
Alternative hypothesis: Ha: μ ≠ 4.7
We have;
Sample size; n = 110
Sample mean; x¯ = 4.6
Variance: σ² = 0.64
Standard deviation; σ = √0.64 = 0.8
Formula for test statistic is;
z = (x¯ - μ)/(σ/√n)
z = (4.6 - 4.7)/(0.8/√110)
z = -0.1/0.0763
z = -1.31
From online p-value from z-score calculator attached, using; z = -1.31, two tailed hypothesis, significance value of 0.1, we have;
P-value = 0.190196
The p-value is greater than the significance value and thus we will fail to reject the null hypothesis and conclude that the mean pressure is not different from 4.7
σ μ
Answer:
24 for 5 is higher because you have to divide 24 by 5 and if you do that it gives you $4.8, while 5 for 24 gives you a unit rate of $0.20.
By reading the given graph with the two linear functions, we want to see at which time do the two bees have the same distance remaining. We will see that the correct option is B, 6 minutes.
So, in the graph, we have distance remaining on the vertical axis and time on the horizontal axis.
We also have two lines, each one describing the distance of each bee as a function of time.
We want to see at which time do the two bees have the same distance remaining, thus, we need to see when the lines intersect (this means that for the same time, the two bees have the same distance remaining).
In the graph, we can see that the intersection happens at the time of 6 minutes, thus the correct option is B; 6 minutes.
If you want to learn more about linear function's graphs, you can read:
brainly.com/question/4025726
This would be 6C3
= 6*5*4
---------- = 20 answer
3*2*1
Answer:
Step-by-step explanation:
The scenario is represented in the attached photo. Triangle ABC is formed. AB represents her distance from her base camp. We would determine BC by applying the law of Cosines which is expressed as
a² = b² + c² - 2abCosA
Where a,b and c are the length of each side of the triangle and B is the angle corresponding to b. It becomes
AB² = AC² + BC² - 2(AC × BC)CosC
AB² = 42² + 28² - 2(42 × 28)Cos58
AB² = 1764 + 784 - 2(1176Cos58)
AB² = 2548 - 1246.37 = 1301.63
AB = √1301.63
AB = 36.08 km
To find the bearing, we would determine angle B by applying sine rule
AB/SinC = AC/SinB
36.08/Sin58 = 42/SinB
Cross multiplying, it becomes
36.08SinB = 42Sin58
SinB = 42Sin58/36.08 = 0.987
B = Sin^-1(0.987)
B = 81°
Therefore, her bearing from the base camp is
360 - 81 = 279°
