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3 years ago

12

Using the coordinate plane below, find the distance between each pair of points. 1. (-3, 6) and (-3, 10) 2. (4, -5) and (-2, -5)

3. (6, 4) and (6, -1) 4. (-9, 1) and (-4, 1)

2 answers:

DochEvi [55]3 years ago

5 0

Answer:

Drag each set of coordinates to the correct location on the table.

Calculate the distance between the pairs of coordinates, and classify them according to the distance between them.

(3, 4) and (2, 1)

(3, 7) and (5, 2)

(5, -2) and (3, 3)

(-2, 3) and (1, 2)

(-4, -2) and (-3, 1)

(4, -1) and (-1, 1)

Step-by-step explanation:

algol133 years ago

4 0

Answer:

1. 4

Step-by-step explanation:

(-3, 6) and (-3, 10)

|-3 - 3| = 0, |6 - 10| = 4

4² + 0² = 16, $\sqrt{16}$ = 4

(4, -5) and (-2, -5)

|4 - -2| = 6, |-5 - 5| = 0

6² + 0² = 36, √36 = 6

(6, 4) and (6, -1)

|6 - 6| = 0, |4 - -1| = 5

5² + 0² = 25, √25 = 5

(-9, 1) and (-4, 1)

|-9 - -4| = 5, |1 - 1| = 0

5² + 0² = 25, √25 = 5

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<u>Step-by-step explanation:</u>

We have , a greenhouse has the shape of a square pyramid. the base has a side length of 30 yards. the height of the greenhouse is 18 yards. We need to find how much space is inside the greenhouse . Let's find out:

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Answer: Medication in Lexi's system on day t becomes,

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Step-by-step explanation:

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3 years ago

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(-1,4) (2,2) find midpoint?

notsponge [240]

$\text{Hey there!}$

$\text{The midpoint formula is: }\dfrac{\mathsf{x_2+x_1}}{2}, \dfrac{\mathsf{y_2+y_1}}{2}$

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

$\mathsf{x_1 = -1}\\\\\mathsf{x_2=2}\\\\\mathsf{y_1=4}\\\\\mathsf{y_2=2}$

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

$\dfrac{2-1}{2}\\\\\mathsf{2-1 = 1}\\\\\mathsf{2=2}\\\\\\\mathsf{x = \dfrac{\mathsf{1}}{2}}$

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$\mathsf{\dfrac{4+2}{2}}\\\\\mathsf{4+2=6}\\\\\mathsf{2=2}\\\\\mathsf{\dfrac{6}{2}=3}\\\\\\\mathsf{y=3}$

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

$\boxed{\boxed{\text{Thus,\ your\ answer\ is:\boxed{(\dfrac{1}{2\ },\ 3)}}}}\checkmark$

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$\text{Good luck on your assignment and enjoy your day!}$

~ $\dfrac{\frak{LoveYourselfFirst}}{:)}$

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