A. left 2 units
the vertex form of a parabola is
y = a(x-h)^2 + k
(h,k) is the point of the vertex
since h is -2 in (x+2)^2
the function is shifted 2 units left
<u>Part A</u>
<u />
So, the x-intercepts are 
<u>Part B</u>
The vertex will be a minimum because the coefficient of
is positive.
The x-coordinate of the vertex is 
Substituting this back into the function, we get 
So, the coordinates of the vertex are 
<u>Part C</u>
Plot the vertex and the x-intercepts and draw a parabola that passes through these three points.
The graph is shown in the attached image.
Answer:
(x²-2x)/(2x+6)
Step-by-step explanation:
When you are asked to divide two fractions just do keep-change-flip. Keep the first fraction, change the ÷ to x and flip the second fraction upside down. So the problem becomes ((x-2)/(x+3)) times (x/2). Then just multiply numerators and multiply denominators.
Answer:
both are equal is 0
Step-by-step explanation:
After substituting, the answer is 0 to both
Seven weeks until they meet again