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2 years ago

a cinder block is sitting on a platform 20 high. lt weighs 79n. The block has_____ energy. calculate it.

1 answer:

3 0

A cinder block is sitting on a platform 20 m high. It weighs 79 N. The block has Gravitational Potential Energy.

Calculations:
Ep = mgh = mg = Fg
Ep = (Fg)(h)
Ep = (79N)(20 m)
Ep = 1580 J.

I believe the block's potential energy with respect to gravity is 1580 J.

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Solve 73 make sure to also define the limits in the parts a and b

Aleks04 [339]

73.

$f(x)=\frac{3x^4+3x^3-36x^2}{x^4-25x^2+144}$

$\lim_{x\to\infty}f(x)=\lim_{x\to\infty}(\frac{3+\frac{3}{x}-\frac{36}{x^2}}{1-\frac{25}{x^2}+\frac{144}{x^4}})=3$ $\lim_{x\to-\infty}f(x)=\lim_{x\to-\infty}(\frac{3+\frac{3}{x}-\frac{36}{x^2}}{1-\frac{25}{x^2}+\frac{144}{x^4}})=3\cdot\frac{1}{2}=3$

Since we can't divide by zero, we need to find when:

$x^4-2x^2+144=0$

But before, we can factor the numerator and the denominator:

$\begin{gathered} \frac{3x^2(x^2+x-12)}{x^4-25x^2+144}=\frac{3x^2((x+4)(x-3))}{(x-3)(x-3)(x+4)(x+4)} \\ so: \\ \frac{3x^2}{(x+3)(x-4)} \end{gathered}$

Now, we can conclude that the vertical asymptotes are located at:

$\begin{gathered} (x+3)(x-4)=0 \\ so: \\ x=-3 \\ x=4 \end{gathered}$

so, for x = -3:

$\lim_{x\to-3^-}f(x)=\lim_{x\to-3^-}-\frac{162}{x^4-25x^2+144}=-162(-\infty)=\infty$ $\lim_{x\to-3^+}f(x)=\lim_{x\to-3^+}-\frac{162}{x^4-25x^2+144}=-162(\infty)=-\infty$

For x = 4:

$\lim_{x\to4^-}f(x)=\lim_{n\to4^-}\frac{384}{x^4-25x^2+144}=384(-\infty)=-\infty$ $\lim_{x\to4^-}f(x)=\lim_{n\to4^-}\frac{384}{x^4-25x^2+144}=384(-\infty)=-\infty$

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What is 4/16 in simplest form?

zlopas [31]

4/16 in simplest form is 1/4 because 4 goes into 4 1 time and 4 goes into 16 4 times

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In a recipe, the ratio of fluid ounces of water to fluid ounces of tomato paste is 3:4. You plan to make 35 fluid ounces of sauc

WITCHER [35]

3:4......added = 7

3/7(35) = 105/7 = 15 oz water
4/7(35) = 140/7 = 20 oz tomato paste <==

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Zolol [24]

The value of this expression when =-2 and x=-1 is: 3.

<h3>Value of the expression</h3>

Given equation:

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Solving the value of the given equation

-2 and x=-1

Hence:

=-(-1)+2

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Therefore the value of this expression when =-2 and x=-1 is: 3.

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