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3 years ago

a cinder block is sitting on a platform 20 high. lt weighs 79n. The block has_____ energy. calculate it.

1 answer:

3 0

A cinder block is sitting on a platform 20 m high. It weighs 79 N. The block has Gravitational Potential Energy.

Calculations:
Ep = mgh = mg = Fg
Ep = (Fg)(h)
Ep = (79N)(20 m)
Ep = 1580 J.

I believe the block's potential energy with respect to gravity is 1580 J.

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Vince is trying to fit two boxes into the trunk of his car. One box is 1/2 of a foot tall and the other is 2 4/5 feet tall. Stac

Nitella [24]

Answer:

3 3/10

Step-by-step explanation:

In order to do this, you need to find the least common multiple. When you do that, you get 5/10 and 2 8/10. Next, what you what to do is turn 2 and 8/10 to an improper fraction, and when you do that you get 28/10. Add 28/10 and 5/10 to get 33/10. Simplify 33/10, and the correct answer is 3 3/10.

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3 years ago

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Dovator [93]

Answer:

1. x = 32°

2. x = 28°

3. x = 15°

4. x = 30°

5. x = 40°

6. x = 20°

Step-by-step explanation:

All the angles should add up to 90° as they are complementary.

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3 years ago

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Plzzz help me with this I’ll give brainliest

scoray [572]

Answer18:

The quadrilateral ABCD is not a parallelogram

Answer19:

The quadrilateral ABCD is a parallelogram

Step-by-step explanation:

For question 18:

Given that vertices of a quadrilateral are A(-4,-1), B(-4,6), C(2,6) and D(2,-4)

The slope of a line is given m= $\frac{Y2-Y1}{X2-X1}$

Now,

The slope of a line AB:

m= $\frac{Y2-Y1}{X2-X1}$

m= $\frac{6-(-1)}{(-4)-(-4)}$

m= $\frac{7}{0}$

The slope is 90 degree

The slope of a line BC:

m= $\frac{Y2-Y1}{X2-X1}$

m= $\frac{6-6}{(-4)-(-1)}$

m= $\frac{0}{(-3)}$

The slope is zero degree

The slope of a line CD:

m= $\frac{Y2-Y1}{X2-X1}$

m= $\frac{(-4)-6}{2-2}$

m= $\frac{-10}{0}$

The slope is 90 degree

The slope of a line DA:

m= $\frac{Y2-Y1}{X2-X1}$

m= $\frac{(-1)-(-4)}{(-4)-(2)}$

m= $\frac{3}{-6}$

m= $\frac{-1}{2}$

The slope of the only line AB and CD are the same.

Thus, The quadrilateral ABCD is not a parallelogram

For question 19:

Given that vertices of a quadrilateral are A(-2,3), B(3,2), C(2,-1) and D(-3,0)

The slope of a line is given m= $\frac{Y2-Y1}{X2-X1}$

Now,

The slope of a line AB:

m= $\frac{Y2-Y1}{X2-X1}$

m= $\frac{2-3}{3-(-2)}$

m= $\frac{-1}{5}$

The slope of a line BC:

m= $\frac{Y2-Y1}{X2-X1}$

m= $\frac{(-1)-2}{2-3}$

m= $\frac{-3}{-1}$

m=3

The slope of a line CD:

m= $\frac{Y2-Y1}{X2-X1}$

m= $\frac{0-(-1)}{(-3)-2}$

m= $\frac{-1}{5}$

The slope of a line DA:

m= $\frac{Y2-Y1}{X2-X1}$

m= $\frac{3-0}{(-2)-(-3)}$

m=3

The slope of the line AB and CD are the same

The slope of the line BC and DA are the same

Thus, The quadrilateral ABCD is a parallelogram

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3 years ago

Two groups of students were asked how far they lived from their school. The table below shows the distances in miles:

pychu [463]

Answer:

C. The value for Group A is double the value for Group B

Step-by-step explanation:

First, you add all the numbers from each group.

A: The distance in total is 39.06

B: The distance in total is 19.53

To find the mean, which is another way of saying the average, you divide the sum with how many numbers there are. (hope this makes sense, I suck at wording)

A: There are 9 numbers in total, hence, 39.06/9 = 4.34

B: There are 9 numbers in total, hence, 19.53/9 = 2.17

Those are the mean distance for the two groups.

2.17 * 2 = 4.34

Hence, C (third statement)

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valina [46]

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