Question

A small business is looking for rectangular warehouses to store extra merchandise. Warehouse A has an area of 6900 ft2. Warehouse B is half as wide and one-third as long. How many square feet is Warehouse B?

Answer 1

Answer:

The area of the warehouse B is 1150 square feet.

Step-by-step explanation:

Let $x$, $y$ are the width and length of the warehouse A, in inches. The areas of the each warehouse are described below:

$A_{A} = x\cdot y$ (1)

$A_{B} = \left(\frac{1}{2}\cdot x \right)\cdot \left(\frac{1}{3}\cdot y \right)$ (2)

Where:

$A_{A}$ - Area of the warehouse A, in square inches.

$A_{B}$ - Area of the warehouse B, in square inches.

If we know that $A_{A} = 6900\,ft^{2}$, then by (1) and (2) we have the following equation:

$A_{B} = \frac{1}{6}\cdot A_{A}$

$A_{B} = 1150\,ft^{2}$

The area of the warehouse B is 1150 square feet.