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3 years ago

Explain how to graph the inequality 8>Y

Mathematics

1 answer:

Colt1911 [192]3 years ago

6 0

Answer:

go on the y-axis and find line 8. draw a line from one side of the graph to the other going through 8. then shade everything BELOW the line. #markasbrainliest

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Jim is showing his work in simplifying (−8.5 + 6.1) − 1.3. Step 1: (6.1 − 8.5) − 1.3 Step 2: 6.1 − (8.5 + 1.3) Step 3: 6.1 − (9.

ra1l [238]

Statement 1 is correct

8 0

3 years ago

Find the area of the composite figure.

Roman55 [17]

Answer:

The Area of the composite figure would be 76.26 in^2

Step-by-step explanation:

According to the Figure Given:

Total Horizontal Distance = 14 in

Length = 6 in

To Find :

The Area of the composite figure

Solution:

Firstly we need to find the area of Rectangular part.

So We know that,

$\boxed{ \rm \: Area \: of \: Rectangle = Length×Breadth}$

Here, Length is 6 in but the breadth is unknown.

To Find out the breadth, we’ll use this formula:

$\boxed{\rm \: Breadth = total \: distance - Radius}$

According to the Figure, we can see one side of a rectangle and radius of the circle are common, hence,

$\longrightarrow\rm \: Length \: of \: the \: circle = Radius$

Since Length = 6 in ;

$\longrightarrow \rm \: 6 \: in = radius$

Hence Radius is 6 in.

So Substitute the value of Total distance and Radius:

Total Horizontal Distance= 14
Radius = 6

$\longrightarrow\rm \: Breadth = 14-6$

$\longrightarrow\rm \: Breadth = 8 \: in$

Hence, the Breadth is 8 in.

Then, Substitute the values of Length and Breadth in the formula of Rectangle :

Length = 6
Breadth = 8

$\longrightarrow\rm \: Area \: of \: Rectangle = 6 \times 8$

$\longrightarrow \rm \: Area \: of \: Rectangle = 48 \: in {}^{2}$

Then, We need to find the area of Quarter circle :

We know that,

$\boxed{\rm Area_{(Quarter \; Circle) } = \cfrac{\pi{r} {}^{2} }{4}}$

Now Substitute their values:

r = radius = 6
π = 3.14

$\longrightarrow\rm Area_{(Quarter \; Circle) } = \cfrac{3.14 \times 6 {}^{2} }{4}$

Solve it.

$\longrightarrow\rm Area_{(Quarter \; Circle) } = \cfrac{3.14 \times 36}{4}$

$\longrightarrow\rm Area_{(Quarter \; Circle) } = \cfrac{3.14 \times \cancel{{36} } \: ^{9} }{ \cancel4}$

$\longrightarrow\rm Area_{(Quarter \; Circle)} =3.14 \times 9$

$\longrightarrow\rm Area_{(Quarter \; Circle) } = 28.26 \: {in}^{2}$

Now we can Find out the total Area of composite figure:

We know that,

$\boxed{ \rm \: Area_{(Composite Figure)} =Area_{(rectangle)}+ Area_{ (Quarter Circle)}}$

So Substitute their values:

$\rm Area_{(rectangle)}$ = 48
$\rm Area_{(Quarter Circle)}$ = 28.26

$\longrightarrow \rm \: Area_{(Composite Figure)} =48 + 28 .26$

Solve it.

$\longrightarrow \rm \: Area_{(Composite Figure)} =\boxed{\tt 76.26 \:\rm in {}^{2}}$

Hence, the area of the composite figure would be 76.26 in² or 76.26 sq. in.

$\rule{225pt}{2pt}$

I hope this helps!

3 0

2 years ago

The length of a rectangle is 7 centimeters greater than the width.

Lisa [10]

Answer:

length = 17cm, width = 10cm

Step-by-step explanation:

2L + 2w = 54

L = w + 7

Substitute:

2(w + 7) + 2w = 54

2w + 14 + 2w = 54

4w = 40

w = 10

L = 10 + 7 = 17

7 0

3 years ago

Can someone do #4 and #5

Hitman42 [59]

Answer:

First, find two points on the graph:

(x₁, y₁) = (0, 2)
(x₂, y₂) = (2, 8)

Slope = $\frac{y_{2}-y_{1} }{x_{2}-x_{1}} = \frac{8-2}{2-0} =\frac{6}{2}=3$

16 + (-3) = 16 - 3 = 13

8 0

3 years ago

stiks02 [169]

Answer:

a. 10, 16

b. 211, 311

c. 10 , 12.5

d. -13, -22

Step-by-step explanation:

In an arithmetic sequence, there is a constant difference, which is the difference between a term and the previous term. We find the constant different for each sequence, and we add it to the second term to find the third term. Then we add the constant difference to the third term to find the fourth term.

4 - (-2) = 6

3rd term: 4 + 6 = 10

4th term: 10 + 6 = 16

111 - 11 = 100

3rd term: 111 + 100 = 211

4th term: 211 + 100 = 311

7.5 - 5 = 2.5

3rd term: 7.5 + 2.5 = 10

4th term: 10 + 2.5 = 12.5

-4 - 5 = -9

3rd term: -4 + (-9) = -13

4th term: -13 + (-9) = -22

4 0

3 years ago