Question

Really need need help on this please

Answer 1

Answer:

$\frac{7}{2}$

Step-by-step explanation:

$\frac{12-3y}{2} + y (\frac{2y-4}{y})$

we substitute the value of "y" in the equation:

$\frac{12-3(3)}{2} + 3 (\frac{2(3)-4}{3})\\\\\frac{12-9}{2} + 3 (\frac{6-4}{3})\\\\\frac{3}{2} + 3 (\frac{2}{3})\\\\\frac{3}{2} + 2\\\\\frac{7}{2}$