Answer:
1. (x + 5)(x +10)
2. (x - 7)( x - 8)
3. (x - 4)( x - 7)
4. 2(7x−1)(x−9)
5. (2x+9)(x+6)
6. (x−1)(x−2)
7. (2x+3)(x+8)
8. (9x−2)(x−7)
9. 6(x−6)(x+7)
10. (9x+10)(x−4)
11. (3x+7)(x+3)
12. (x−9)(x−9)
13. 4(9x−10)(x−8)
14. 3(x+3)(x−9)
15. 2(x−1)(x+3)
16. 2(3x−1)(x+2)
17. 5(x−2)(x−2)
18. 2(x−1)(x−2)
Step-by-step explanation:
I'm so sorry it took this long that made my brain hurt it was worth it
Sorry it took so long..
hope I helped!!
The two numbers are 30 and 11
<em><u>Solution:</u></em>
Given that we have to separate the number 41 into two parts
Let the second number be "x"
<em><u>Given that first number is eight more than twice the second number</u></em>
first number = eight more than twice the second number
first number = 8 + twice the "x"
first number = 8 + 2x
So we can say first number added with second number ends up in 41
first number + second number = 41
8 + 2x + x = 41
8 + 3x = 41
3x = 41 - 8
3x = 33
x = 11
first number = 8 + 2x = 8 + 2(11) = 8 + 22 = 30
Thus the two numbers are 30 and 11
Check the picture below, notice those three quadrilaterals.
the square, is really a rectangle and is also a rhombus, but with right-angles and equal sides.
Answer:
Jim will be paid $150 or 30% to his account.
Step-by-step explanation:
Have a great day :)
Answer:
x=π/2 ,3π/2
Step-by-step explanation:
cot x(csc x+1)=0
either cot x=0
tanx=∞=tan (π/2)
x=π/2
or csc x=-1
or sin x=-1=-sin (π/2)=sin (π+π/2)=sin (3π/2)
x=3π/2
