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Paul [167]
2 years ago
8

Find five rational numbers between 2/3 and 4/5

Mathematics
1 answer:
ch4aika [34]2 years ago
4 0

Answer:

Find five rational numbers between 2/3 and 4/5 -

61/90 62/90 63/90 64/90 65/90 66/90 67/90

choose any five :)

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Which is factorial using integers?<br> a) y+25<br> b) y^2-25<br> c) y^2+25<br> d) y-10<br> e) y^2+10
Masteriza [31]

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Write down the next term in each of the following sequences
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As of April 2006, roughly 50 million web domain names were registered (e.g., ). How many domain names consisting of just two let
Furkat [3]

Answer:

a) 676, 1296

b) 17576, 46656

c) 456976, 1679616

Step-by-step explanation:

firstly we know that there are 26 letters in the alphabet.

there are 26 ways of choosing the first character and 26 ways choosing the second character,

Therefore, the possible number of domains with two leeter is;

n = 26²

= 26 × 26

= 676

now when the digits are allowed, there are 26 + 10 = 36 characters to be used in total

therefore the possible number of domains with two characters is;

n = 36²

= 36 × 36

= 1296

b)

there are 26 ways of choosing each character

therefore, the possible number of domains with three letters is

n = 26³

= 26 × 26 × 26

= 17576

when the digits are allowed, there are 26 + 10 = 36 characters to be used in total

therefore , the possible number of domains with three characters is;

n = 36³

= 36 × 36 × 36

= 46656

c)

there are 26 ways of choosing each character, therefore the possible number of domains with four letters is;

n = 26⁴

n = 26 × 26 × 26 × 26

n = 456976

when the digits are allowed, there are 26 + 10 = 36 characters to be used in total

therefore, the possible number of domains with four characters is;

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n = 36 × 36 × 36 × 36

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7 0
3 years ago
For the cereal box, name each of the following
zaharov [31]

Answer:

AB , AD , EF , EH all intersect AE ⇒ answer (c)

Step-by-step explanation:

∵ AE segment passing through A and E

∴ Each segment passing through A and E intersects AE

∴ AB intersects AE at A

∴ AD intersects AE at A

∴ EF intersects AE at E

∴ EH intersects AE at E

∴ The answer is (c)

Step-by-step explanation:

8 0
3 years ago
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