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Murljashka [212]
3 years ago
9

The time to failure (in hours) of fans in a personal computer can be modeled by an exponential distribution with l=0.0003

Mathematics
1 answer:
Dvinal [7]3 years ago
3 0

Answer: 0.0497870 ; 0.87754

Step-by-step explanation:

Given that :

λ = 0.0003

Defining a continuous distribution function :

F(x) = 1 - e^-λx = 1 - e^-0.0003x ; x ≥ 0

a. What proportion of the fans will last at least 10,000 hours?

P(x ≥ 10000) = e^-0.0003(10000) = 0.0497870

b. What proportion of the fans will last at most 7000 hours?

P(x ≥ 7000) = 1 - p(x ≤ 7000) = 1 - e^-0.0003(7000)

1 - 0.12245642825 = 0.87754

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your uncle jim lives in england, where the current exchange rate is 1.64 US dollars for each British pound. Solve for the amount
Talja [164]

Based on the amount of your monthly bill, if you lived in England, your bill to the nearest hundredth is $185.82

<h3>How to find your bill in pound sterling?</h3>

You have a monthly bill of $304.72. If this was also your bill in England id you stayed there, it would need to be converted to pounds. The way to do this is by using the exchange rate.

If each British Pound is $1.64 U.S. Dollar, then the value of your monthly bill if you lived in England is:

= Monthly bill in dollars / Conversion or exchange rate

= 304.72 / 1.64

= $185.82

Find out more on the exchange rate at brainly.com/question/20332320

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7 0
1 year ago
Use the laplace transform to solve the given initial-value problem. y'' − 4y' + 4y = t3e2t, y(0) = 0, y'(0) = 0
DanielleElmas [232]

The Laplace of the given equation is y=-\frac{15e^2}{8}e^{2t}+\left(-3e^2+\frac{15e^2}{4}\right)e^{2t}t+\frac{e^2t^4}{4}+e^2t^3+\frac{9e^2t^2}{4}+3e^2t+\frac{15e^2}{8}.

According to the statement

we have given that the equation and we have to solve this problem with the help of the Laplace transform.

So, According to the statement

the given equation is

y'' − 4y' + 4y = t^3e^2t, y(0) = 0, y'(0) = 0

And the Laplace transform is an integral transform method which is particularly useful in solving linear ordinary differential equations.

Firstly fill the value of the Laplace of the second order derivative and put x = 0 in the equation

And same it with the first order of the derivative.

And then the Laplace of the equation become

y=-\frac{15e^2}{8}e^{2t}+\left(-3e^2+\frac{15e^2}{4}\right)e^{2t}t+\frac{e^2t^4}{4}+e^2t^3+\frac{9e^2t^2}{4}+3e^2t+\frac{15e^2}{8}

So, The Laplace of the given equation is y=-\frac{15e^2}{8}e^{2t}+\left(-3e^2+\frac{15e^2}{4}\right)e^{2t}t+\frac{e^2t^4}{4}+e^2t^3+\frac{9e^2t^2}{4}+3e^2t+\frac{15e^2}{8}

Learn more about Laplace transform here

brainly.com/question/17062586

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5 0
2 years ago
Find an explicit solution of the given initial-value problem.dy/dx = ye^x^2, y(3) = 1.
tamaranim1 [39]

Answer:

y=exp(\int\limits^x_4 {e^{-t^{2} } } \, dt)

Step-by-step explanation:

This is a separable equation with an initial value i.e. y(3)=1.

Take y from right hand side and divide to left hand side ;Take dx from left hand side and multiply to right hand side:

\frac{dy}{y} =e^{-x^{2} }dx

Take t as a dummy variable, integrate both sides with respect to "t" and substituting x=t (e.g. dx=dt):

\int\limits^x_3 {\frac{1}{y} } \, \frac{dy}{dt} dt=\int\limits^x_3 {e^{-t^{2} } } dt

Integrate on both sides:

ln(y(t))\left \{ {{t=x} \atop {t=3}} \right. =\int\limits^x_3 {e^{-t^{2} } } \, dt

Use initial condition i.e. y(3) = 1:

ln(y(x))-(ln1)=\int\limits^x_3 {e^{-t^{2} } } \, dt\\ln(y(x))=\int\limits^x_3 {e^{-t^{2} } } \, dt\\

Taking exponents on both sides to remove "ln":

y=exp (\int\limits^x_3 {e^{-t^{2} } } \, dt)

7 0
3 years ago
How can you compare 5/8 and 1/2 without using a model?
Lapatulllka [165]
Well, you can ask yourself what is half of eight and thats it. btw 5/8 is larger

6 0
4 years ago
Three tanks,A,B,C are used to store oil. Tank A contains 'n' litres of oil. Tank B contains (n+150) litres of oil. Tank C is emp
Yuliya22 [10]
500 divide by 300 is 150
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3 years ago
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