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LuckyWell [14K]
2 years ago
7

7 Find mzx. X (2x + 22)° (9x – 15) Z Y (4x + 11) W

Mathematics
1 answer:
kakasveta [241]2 years ago
7 0

Answer:

Step-by-step explanation:

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ASAP 25 POINTS WILL MARK BRAINLIEST MULTIPLE CHOICE
Natasha_Volkova [10]

Answer:

Yes, this is a translation which doesn't change the pre-image size

Step-by-step explanation:

4 0
3 years ago
Solve for (0,2π]<br> 2cos ß * sin ß = cos ß
Temka [501]

Given :

An equation, 2cos ß sin ß = cos ß .

To Find :

The value for above equation in (0, 2π ] .

Solution :

Now, 2cos ß sin ß = cos ß

2 sin ß = 1

sin ß = 1/2

We know, sin ß = sin (π/6)  or sin ß = sin (5π/6) in  ( 0, 2π ] .

Therefore,

\beta = \dfrac{\pi}{6}\ or\ \beta = \dfrac{5\pi}{6}

Hence, this is the required solution.

4 0
2 years ago
If a fire is burning a building and it takes 2 hours to put it out using 2000 gal./min., what minimum diameter cylindrical tank
strojnjashka [21]

Answer:

The minimum diameter of the cylindrical tank needed to store the quantity needed to put out the fire is approximately 58.415 feet.

Step-by-step explanation:

A gallon equals 0.134 cubic feet. First, we determine the amount of water (Q), measured in cubic feet, needed to put out the fire under the assumption that water is consumed at constant rate:

Q = \dot Q \cdot \Delta t (1)

Where:

\dot Q - Volume rate, measured in feet per minute.

\Delta t - Time, measured in minutes.

If we know that \dot Q = 2000\,\frac{gal}{min} and \Delta t = 120\,min, then the amount of water is:

Q = \left(2000\,\frac{gal}{min} \right)\cdot (120\,min) \cdot \left(0.134\,\frac{ft^{3}}{gal} \right)

Q = 32160\,ft^{3}

And the diameter of the cylindrical tank based on the capacity found above is determined by volume formula for a cylinder:

Q = \frac{\pi}{4}\cdot D^{2}\cdot h (2)

Where:

D - Diameter, measured in feet.

h - Height, measured in feet.

If we know that Q = 32160\,ft^{3} and h = 12\,ft, then the minimum diameter is:

D^{2} = \frac{4\cdot Q}{\pi\cdot h}

D = 2\cdot \sqrt{\frac{Q}{\pi\cdot h} }

D = 2\cdot \sqrt{\frac{32160\,ft^{3}}{\pi\cdot (12\,ft)} }

D \approx 58.415\,ft

The minimum diameter of the cylindrical tank needed to store the quantity needed to put out the fire is approximately 58.415 feet.

8 0
2 years ago
Decide whether quadrilateral JKLM is a rectangle, a rhombus, or a square. More than one answer may apply!
NARA [144]

Answer:

Square.

Step-by-step explanation:

given J(-4,2) || K(0,3) || L(1,-1) || M(-3,-2)

given below the visual answer.

OR

you can find the distance of coordinate to coordinate:

Distance of JK

√(-4-0)² + (2-3)²

√17

Distance of KL

√(0-1)²+(3--1)²

√17

Distance of LM

√(1--3)²+(-1--2)²

√17

Distance of MJ

√(-3--4)²+(-2-2)²

√17

All sides are similar of √17 , so its a square.

4 0
2 years ago
Read 2 more answers
A triangle has a base of 4x-7 and a height of 2x + 3. Find the area.
wolverine [178]

Answer:

area = ‐11

Step-by-step explanation:

hope this is correct and helps

7 0
3 years ago
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