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Karolina [17]
2 years ago
9

Pls answer

Mathematics
1 answer:
Stels [109]2 years ago
5 0

Answer:

b-2=n

Step-by-step explanation:

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20 POINT QUESTION!!<br><br> Complete the equation of the linear function.<br><br><br> y = <br> x +
Viefleur [7K]
A=(0,1); B=( \frac{1}{2}, 0) \\ &#10;y=ax+b&#10; &#10;\left \{ {{1=0a+b} \atop {0= \frac{1}{2}+b }} \right.  \\ &#10; \left \{ {{1=b} \atop { \frac{1}{2}a=-b}} \right.  \\ &#10; \left \{ {{b=1} \atop {a=-2}} \right. &#10;&#10;y=-2x+1
8 0
3 years ago
Help! Math Homework.
Alenkinab [10]
To solve problem 1 what you need to do is figure out how many miles the girls have walked so far and then subtract that from the total distance they must complete.

3/4-(3/10+1/4)

Step 1:Change the denominators so that way they are all the same

3/4=15/20
3/10=6/20              15/20-(6/20+5/20)
1/4=5/20

Step 2: Begin solving the problem

6/20+5/20=11/20
15/20-11/20=4/20

Step 3: Simplify your answer

4/20=1/5

Step 4 (is optional): Write your answer in a complete statement

The three girls walk 1/5mile together to school

Answer: A

I hope this is correct and if not I apologize for giving false information.

8 0
3 years ago
PLEASE HELP, DUE IN 2 HOURS ((btw i would figure it out but i’m tired and too lazy, thanks!)) and i need question 1-3, all three
zlopas [31]

Answer:

THIS MIGHT HELP U ....

7 0
2 years ago
A number 1 is less than 5 and greater than 3. Show work pleaseee
Readme [11.4K]
1<5>3. that’s the answer you’re looking for i think?? no work to be show
4 0
2 years ago
A researcher wants to test if the mean annual salary of all lawyers in a city is different from $110,000. A random sample of 50
KiRa [710]

Solution :

This is the two tailed test.

The null hypothesis and the alternate hypothesis is as :

Null hypothesis is $H_0:\mu=110000$

Alternate hypothesis is $H_0:\mu \neq110000$

$\overline x = 112000, \ \mu = 110000, \sigma = 16100, n =  50, \alpha = 0.02$

Therefore, the critical value of z is :

$z_{\alpha} = -2.33 \text{ and}\  2.33$

Now the test statics is :

$z=\frac{\frac{(\overline x - \mu)}{\sigma}}{\sqrt n}$

$z=\frac{\frac{(112000-110000)}{16100}}{\sqrt {50}}$

$z=0.87$

The test statics is 0.878

We see that it is a right tailed test.

$P(z > 0.878)=1-P(z

$P- \text{value}= \ 2 \times 0.19$

              = 0.3800

Thus , P-value > α

So we fail to reject the null hypothesis.

5 0
2 years ago
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