Honestly I think you should ask your teacher abt this to be honest because this looks really hard
Answer:
the second option
Step-by-step explanation:
pretty sure it's the second option
hope this helped ;)
Answer:
Step-by-step explanation:
<h3>Given</h3>
<u>Inequality</u>: (x-1)(x+2)(2x-7)≤0
<h3>Solution: </h3>
<u>If we solve the corresponding equation (x-1)(x+2)(2x-7)²= 0, we get roots </u>
<u>We need to consider the following 4 intervals: </u>
- (−∞; −2), [−2; 1], (1; 3.5), (3.5; ∞)
<u>1st interval</u> (−∞; −2)
- The expression (x-1)(x+2)(2x-7)² is positive as two of the multiples are negative and one is always positive (square number), and therefore does not satisfy the inequality.
<u>2nd interval</u> [−2; 1]
- The expression is negative as only one of the multiples is negative, and therefore the interval (−1; 2) satisfies the inequality.
<u>3rd interval</u> (1; 3.5)
- The expression is positive as all the multiples are positive. Therefore, the interval (1; 3.5) also does not satisfy the inequality.
<u>4th interval</u>
- The expression is positive as above, and therefore also does not satisfy the inequality.
<u>So, the answer to the inequality is:
</u>
When i calculated it , it says 993.813
