Answer:
D. y ≥ 0
Step-by-step explanation:
The range of the function refers to the possible y values which come under the limits of the function.
Here, we can see that no y values are less than 0.
Hence, the range of the function is :
D. y ≥ 0
B,C,A is the answer to your question
Answer:
See attached for the cyclic quadrilateral
To prove: <BAD + <BCD =180°
Construction: Join B and D to the centre O of circle ABCD
Proof
With the lettering of the attached drawing,
<BOD = 2y (angle at centre is 2 X angle at circumference)
Reflex <BOD = 2x (angle at centre is 2 X angle at circumference)
∴ 2x + 2y = 360° (angle at point)
∴ x + y = 180°
∴ <BAD + <BCD = 180°
Step-by-step explanation:
The vertices of a cyclic quadrilateral lie on the circumference of the circle and the opposite angles of a cyclic quadrilateral lie in opposite segment of a circle.
The question is to prove that the opposite angles of a cyclic quadrilateral are supplementary that is 180°. Another way of stating this theory is 'Angles in opposite segments are supplementary'.
Note that the sum of supplementary angles is 180°.
x to both sides
2 = 3x + 1
subtract 1 from both sides
1 = 3x
divide both sides by 3.
x = 1/3
plug this guy into one of the equations to get y = 5/3.
Step-by-step explanation:
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