Question

The population of deer in a forest was measured to be 1,938 in the year 2010. If the population increased by a steady rate of 4% per year, which of the following calculations would predict its population in 2013?

Answer 1

2179(.4) because you have to divide 1938 by 100 times it by 4 add 1938 then repeat for that answer twice more

Answer 2

Answer:

Hence, the population of deer in the year 2013 will be:

2180.

Step-by-step explanation:

It is given that:

The population of deer in a forest was measured to be 1,938 in the year 2010.

If the population increased by a steady rate of 4% per year.

Let P(t) denotes the population of the deer in the forest in 't' years.

This means that the population function P(t) can be defined as:

$P(t)=1938\times (1+0.04)^t$

i.e. in the year 2010 let t=0.

in the year 2011 let t=1.

in the year 2012 t=2

and in the year 2013, t=3

Hence, the population of the deer in the year 2013 is given by:

$P(t)=1938\times (1+0.04)^3\\\\P(t)=1938\times (1.04)^3\\\\\\P(t)=2179.98$

which is approximately given as:

$P(t)=2180$

Hence, the population of deer in the year 2013 will be:

2180.