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3 years ago

Please please jhelp me....

Mathematics

1 answer:

Mrrafil [7]3 years ago

6 0

Answer:

2·v - (u + w) = (5, 0, -10)

Step-by-step explanation:

The given values of the vectors are;

u = (2, -1, 3), v = (4, 0, -2), and w = (1, 1, 3)

The required vector is 2·v - (u + w)

2 × v = 2 × (4, 0, -2) = (8, 0, -4)

(u + w) = (2, -1, 3) + (1, 1, 3) = (3, 0, 6)

Therefore;

2·v - (u + w) = (8, 0, -4) - (3, 0, 6) = (5, 0, -10)

2·v - (u + w) = (5, 0, -10)

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What is square root of 126 + square root of 56 in standard form

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3 years ago

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Find parametric equations for the tangent line to the curve with the given parametric equations at the specified point. x = e−5t

Elan Coil [88]

Answer:

x = 1 - 5t

y = t

z = 1 - 5t

Step-by-step explanation:

For the equation of a line, we need a point and a direction vector. We are given a point (1, 0, 1).

Since the line is suppose to be a tangent to the given curve at the point (1, 0, 1), we need to find a tangent vector for which the curve passes through that point.

We have x = e^(-5t)cos5t

at t = 1, x = e^(-5)cos5

at t = 0, x = 1

y = e^(-5t)sin5t

at t = 1, y = e^(-5)sin5

at t = 0, y = 0

z = e^(-5t)

at t = 1, z = e^(-5)

at t = 0, z = 1

Clearly, the only parameter value for which the curve passes through the point (1, 0, 1) is t = 0.

In vector notation, the curve

r(t) = xi + yj + zk

= e^(-5t)cos5t i + e^(-5t)sin5t j + e^(-5t) k

r'(t) = [-5e^(-5t)cos5t - e^(-5t)sin5t] i +[e^(-5t)cos5t - 5e^(-5t)sin5t] j - 5e^(-5t) k

r'(0) = -5i + j - 5k

is a vector tangent at the point.

We get the parametric equation from this.

x = x(0) + tx'(0)

= 1 - 5t

y = y(0) + ty'(0)

= t

z = z(0) + tz'(0)

= 1 - 5t

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3 years ago

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Step-by-step explanation:

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3 years ago

1/6 of ... is 12. please help! hahaha nevermind i read the question wrong sorry all those smart people out there

ludmilkaskok [199]

Answer:

Step-by-step explanation:

Dont worry, these problems are tricky! The answer is 72. All you have to do to find the answer is multiply 12x6. For example, if it was asking '1/8 of ... is 12' then you would multiply 12x8.

Hope this helps! I would really appreciate it if you marked me brainliest! :)

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3 years ago

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Plz help I will give you BRAINLIESt 5stars

Svetradugi [14.3K]

Answer:

I will just give you the way of solving it

Step-by-step explanation:

First you have to change the sgape of the equation and it will become like this :

-6y=-2x+12

And then:

Y=0.33x+2

And then you have to give values to x and find y

For example i will make x zero (0)

It will become

Y=0.33(0)+12

=+12

And the points are (0,+12)

Go on like this and draw the line

Good luck

Sorry for bad english

4 0

3 years ago

Please please jhelp me....​

Please please jhelp me....