10 is your common difference
The classifications of the functions are
- A vertical stretch --- p(x) = 4f(x)
- A vertical compression --- g(x) = 0.65f(x)
- A horizontal stretch --- k(x) = f(0.5x)
- A horizontal compression --- h(x) = f(14x)
<h3>How to classify each function accordingly?</h3>
The categories of the functions are given as
- A vertical stretch
- A vertical compression
- A horizontal stretch
- A horizontal compression
The general rules of the above definitions are:
- A vertical stretch --- g(x) = a f(x) if |a| > 1
- A vertical compression --- g(x) = a f(x) if 0 < |a| < 1
- A horizontal stretch --- g(x) = f(bx) if 0 < |b| < 1
- A horizontal compression --- g(x) = f(bx) if |b| > 1
Using the above rules and highlights, we have the classifications of the functions to be
- A vertical stretch --- p(x) = 4f(x)
- A vertical compression --- g(x) = 0.65f(x)
- A horizontal stretch --- k(x) = f(0.5x)
- A horizontal compression --- h(x) = f(14x)
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Answer: 30 Pins
Step-by-step explanation:
I solved it on khan academy
Answer:
Okay so, first put a dot on the number three. Next, go down one and over two from that spot (2, 2) and so on.
Step-by-step explanation:
The first line is perpendicular, the second line is not perpendicular and not parallel , the third line is parallel to the above line and the forth line not parallel or perpendicular to the line.
<h3>How can the slope of the line be calculate?</h3>
The slope of the line is been given as −3x+5y=−15
Then 
, hence the slope is 
- Slope of the first line 5x + 3y = 15 after calculation is
the slope is 
this means that the line is perpendicular to the given line
- Slope of the second line 3x + 5y = 15 after calculation is
This means that the line is not perpendicular and not parallel
- Slope of the Third line -3x + 5y = 15 can be calculated as
This means that the line is parallel to the above line.
- Slope of the first line 3x + 5y = 15 after calculation is
This means that the line is not parallel or perpendicular to the line
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