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Gnesinka [82]
3 years ago
5

What is the measure of angle x? Show or explain how you know.

Mathematics
1 answer:
arsen [322]3 years ago
8 0

Answer:

65 degrees

Step-by-step explanation:

y is a right angle and a is 30 degrees. this means that the supplementary engle of x is 45 plus 70 which is 115. 180-115 = 65 degrees.

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Last year, nine employees of an electronics company retired. Their ages at retirement are listed below.
GuDViN [60]

Answer:

58.0

Step-by-step explanation:

Given the data:

56 65 62 53 68 58 65 52 56

Reorderd data: 52, 53, 56, 56, 58, 62, 65, 65, 68

Median = 1/2(n + 1) th term

n = sample size = 9

Hence,

Median = 1/2(9 + 1)th term

Median = 1/2(10)th term

Median = 5th term

5th term in the reordered data = 58

Hence, median age is 58

7 0
3 years ago
I really need help with my homework. <br><br> factorise 10x+25
alina1380 [7]
5(2x + 5), because 10x and 25 only have 5 in common, which is why it's outside the bracket, and 5 × 2x is 10x, and 5 × 5 is 25. Hope this helps!
6 0
3 years ago
Read 2 more answers
Help please..................
Svetradugi [14.3K]
Substitute p and q with the given numbers (6 and 5) then use pemdas
18+42/6-5= 20
4 0
2 years ago
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In a study of 225 adults, the mean heart rate was 72 beats per minute. Assume the population of heart rates is known to be appro
Aleonysh [2.5K]
<span> The lower and upper bounds of the confidence intervals must be equally distanced from the mean 
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</span><span>70.9 - 73.1 
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3 0
2 years ago
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2 tan 30°<br>II<br>1 + tan- 300​
shusha [124]

Question:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}

Answer:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}= sin(60^{\circ})

Step-by-step explanation:

Given

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}

Required

Simplify

In trigonometry:

tan(30^{\circ}) = \frac{1}{\sqrt{3}}

So, the expression becomes:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{2 * \frac{1}{\sqrt{3}}}{1 + (\frac{1}{\sqrt{3}})^2}

Simplify the denominator

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{2 * \frac{1}{\sqrt{3}}}{1 + \frac{1}{3}}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{\frac{2}{\sqrt{3}}}{1 + \frac{1}{3}}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{\frac{2}{\sqrt{3}}}{ \frac{3+1}{3}}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{\frac{2}{\sqrt{3}}}{ \frac{4}{3}}

Express the fraction as:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}= \frac{2}{\sqrt 3} / \frac{4}{3}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{2}{\sqrt 3} * \frac{3}{4}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{1}{\sqrt 3} * \frac{3}{2}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{3}{2\sqrt 3}

Rationalize

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{3}{2\sqrt 3} * \frac{\sqrt{3}}{\sqrt{3}}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{3\sqrt{3}}{2* 3}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{\sqrt{3}}{2}

In trigonometry:

sin(60^{\circ}) =  \frac{\sqrt{3}}{2}

Hence:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}= sin(60^{\circ})

3 0
3 years ago
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