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3 years ago

6

Giving away 100 points :) Hope you have a nice day

2 answers:

Lady_Fox [76]3 years ago

8 0

Answer: No way!! Thank you so much!!

Step-by-step explanation:

Verizon [17]3 years ago

5 0

Answer:

THANKS BRO

Step-by-step explanation:

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If f(x) = 5x + 40, what is f(x) when x = -5?<br> оооо

mote1985 [20]

I think it’s 15..
cause you replace the x with -5 and solve the problem

8 0

3 years ago

I need this Please help me

ANEK [815]

9514 1404 393

Answer:

(c) Not parallel: corresponding angles are not congruent

Step-by-step explanation:

The two angles shows are both "east" of the respective points of intersection, so are "corresponding" angles. If (and only if) lines r and s are parallel, corresponding angles are congruent. These angles have different measures, so lines r and s are not parallel.

4 0

3 years ago

1 point<br> 10. What is the solution of the system of equations graphed below?*

Tema [17]

Answer:

No solution

Step-by-step explanation:

Unfortunately your screenshot has cut off the final answer choice, if it says "no solution" you should choose that because these two lines are parallel. Meaning they will never intersect, and the point of intersection is usually the solution.

5 0

3 years ago

a right prism with a base perimeter of 9 units a height of 5 units and a total base of 16 square units has a surface area of how

slava [35]

The answer is 80 because of 16 times 5 that's how you get your answer

hope this helps :)

4 0

3 years ago

A teacher places n seats to form the back row of a classroom layout. Each successive row contains two fewer seats than the prece

Alex_Xolod [135]

Answer:

The number of seat when n is odd $S_n=\frac{n^2+2n+1}{4}$

The number of seat when n is even $S_n=\frac{n^2+2n}{4}$

Step-by-step explanation:

Given that, each successive row contains two fewer seats than the preceding row.

Formula:

The sum n terms of an A.P series is

$S_n=\frac{n}{2}[2a+(n-1)d]$

$=\frac{n}{2}[a+l]$

a = first term of the series.

d= common difference.

n= number of term

l= last term

$n^{th}$ term of a A.P series is

$T_n=a+(n-1)d$

n is odd:

n,n-2,n-4,........,5,3,1

Or we can write 1,3,5,.....,n-4,n-2,n

Here a= 1 and d = second term- first term = 3-1=2

Let $t^{th}$ of the series is n.

$T_n=a+(n-1)d$

Here $T_n=n$ , n=t, a=1 and d=2

$n=1+(t-1)2$

⇒(t-1)2=n-1

$\Rightarrow t-1=\frac{n-1}{2}$

$\Rightarrow t = \frac{n-1}{2}+1$

$\Rightarrow t = \frac{n-1+2}{2}$

$\Rightarrow t = \frac{n+1}{2}$

Last term l= n,, the number of term $=\frac{ n+1}2$ , First term = 1

Total number of seat

$S_n=\frac{\frac{n+1}{2}}{2}[1+n}]$

$=\frac{{n+1}}{4}[1+n}]$

$=\frac{(1+n)^2}{4}$

$=\frac{n^2+2n+1}{4}$

n is even:

n,n-2,n-4,.......,4,2

Or we can write

2,4,.......,n-4,n-2,n

Here a= 2 and d = second term- first term = 4-2=2

Let $t^{th}$ of the series is n.

$T_n=a+(n-1)d$

Here $T_n=n$ , n=t, a=2 and d=2

$n=2+(t-1)2$

⇒(t-1)2=n-2

$\Rightarrow t-1=\frac{n-2}{2}$

$\Rightarrow t = \frac{n-2}{2}+1$

$\Rightarrow t = \frac{n-2+2}{2}$

$\Rightarrow t = \frac{n}{2}$

Last term l= n, the number of term $=\frac n2$ , First term = 2

Total number of seat

$S_n=\frac{\frac{n}{2}}{2}[2+n}]$

$=\frac{{n}}{4}[2+n}]$

$=\frac{n(2+n)}{4}$

$=\frac{n^2+2n}{4}$

4 0

3 years ago