We have been given that Jackson purchases a new car for $48,000. The car's value can be modeled by the following exponential function:
where y represents the car's value and t represents time in years. We are asked to find the decay rate as a percentage.
We know that an exponential decay function is in form
, where,
y = Final value,
a = Initial value,
r = Decay rate in decimal form,
x = time.
Upon comparing our given function
with standard decay function
, we can see that
.
Let us solve for r.



Let us convert 0.24 into percentage.

Therefore, the decay rate is 24%.
Answer:
The only difference is that for any positive value of 'x' g(X) and h(X) will be same and for any negative value of 'x' g(x) and h(x) will be different.
Step-by-step explanation:
Given


|x| is modulus of x so modulus makes negative value as psoitive
for example


now we will solve for the above
For 

and

Now for 

and

so for positive value it is same and for negative value it is different
I am unsure about the very last problem but I can help with the first two
1) (y+1)+4
If we combine the numbers 1 and 4, we get +5 and can isolate the numbers from the variable.
This would give us

2) (6*r)*7
remember that we do not have to explicitly state 6*r
Instead, we can write it as 6r
this helps us get rid of the parentheses
now we can write it as

I hope this helps!:)
Answer:
Step-by-step explanation:
<u>Use properties of exponents:</u>
<u>Simplify the given expression:</u>
- 3⁴⋅x⋅(3/x²)⁻² =
- 3⁴·x·(3x⁻²)⁻² =
- 3⁴·x·(3⁻²)(x⁻²ˣ⁻²) =
- 3⁴⁻²·x¹⁺4 =
- 3²·x⁵ =
- 9x⁵
All three are similar
In ∆SUT and ∆VWX
- Two sides are similar and one angle is similar
So by SSA they are similar
In ∆PRQ and rest two
All angles are.
So
They are similar by AAA congruence