Factor the expression x2 - 49.<br> A. 7(x² – 7)<br> B. 7.(2-7)<br> C. 2+7(2-7)<br> D. (x + 7)(x-7)

Amira and Mandisa sell balloon animals at different stands on the boardwalk. They each use a constant number of balloons per ani

MAXImum [283]

Mandisa uses 5 balloons for each animal, this means that Mandisa uses more.

<h3>Linear equation</h3>

Linear equation is in the form:

y = mx + b

where y, x are variables, m is the slope of the line and b is the y intercept.

Let y represent the number of balloons for x animals.

Amira uses 4 balloons for each animal.

For Mandisa, using the table using (20, 225) and (60, 25):

$slope(m)=\frac{y_2-y_1}{x_2-x_1}=\frac{25-225}{60-20}=-5$

Therefore Mandisa uses 5 balloons for each animal, this means that Mandisa uses more.

Find out more on linear equation at: brainly.com/question/14323743

6 0

2 years ago

What is the diameter of 144πm2??

Neko [114]

4(pi)m^2 = 144(pi)
4m^2 = 144

m^2 = 36
m = 6cm

diameter = 2m
= 2(6)
= 12cm

3 0

3 years ago

Read 2 more answers

For concreatting a tower cement, sand, stones are in the ratio 1:2:4 For 144kg sand.. What amount of cement is required?

Verdich [7]

Answer:

72 kg

Step-by-step explanation:

For concreatting a tower cement, sand, stones are in the ratio 1:2:4 For 144kg sand.. What amount of cement is required?

We are given the ratio

cement: sand:stones

= 1:2:4

The sum of proportion =

1 + 2 + 4 = 7

We are given the kg of sand = 144kg

Step 1

We find the total kg of cement, sand and stones = x

Using the proportion of sand,

2/7 of x = 144kg

2/7 × x = 144kg

2x/7 = 144kg

Cross Multiply

2x = 7 × 144kg

x = 7 × 144kg/2

x = 504kg

Therefore the total kg of cement, sand and stone = 504kg

Step 2

The amount of cement required is calculated as:

1/7 × 504 kg = 72 kg

Therefore, 72kg of cement is required.

4 0

3 years ago

In a random sample of 8 people, the mean commute time to work was 33.5 minutes and the standard deviation was 7.2 minutes. A 95

Elina [12.6K]

Answer: Margin of error = 6.58

Confidence interval = (26.91, 40.08)

Step-by-step explanation:

Since we have given that

Sample size n = 8

Sample mean = 33.5 minutes

Population standard deviation = 9.5 minutes

At 95% confidence interval,

α = 0.05

t = 1.96

So, Margin of error is given by

$t\times \dfrac{\sigma}{\sqrt{n}}\\\\=1.96\times \dfrac{9.5}{\sqrt{8}}\\\\=6.58$

Confidence interval would be

Lower limit:

$\bar{x}-6.58\\\\=33.5-6.58\\\\=26.91$

Upper limit:

$\bar{x}+6.58\\\\=33.5+6.58\\\\=40.08$

Hence, the interval would be (26.91, 40.08)

But at standard deviation 7.2 minutes, the confidence interval was (27.5, 39.5)

Confidence interval using the standard normal distribution is wider than the confidence interval using t distribution.

3 0

3 years ago

Given that m∠TSU = m∠SUQ, why is RT || UQ?

o-na [289]

The answer to your question is option A

6 0

2 years ago

Factor the expression x2 - 49. A. 7(x² – 7) B. 7.(2-7) C. 2+7(2-7) D. (x + 7)(x-7)