i. Let t be the line tangent at point J. We know that a tangent line at a point on a circle, is perpendicular to the diameter comprising that certain point. So t is perpendicular to JL
let l be the tangent line through L. Then l is perpendicular to JL ii. So t and l are 2 different lines, both perpendicular to line JL.
2 lines perpendicular to a third line, are parallel to each other, so the tangents t and l are parallel to each other.
Remark. Draw a picture to check the
Answer:
A) Slope = -2 and y-int = 1
Step-by-step explanation:
The easiest way to get the slope and y-intercept from an equation is to put it in slope-intercept form: y = mx + b, where m is the slope and b is the y-intercept.
So, let's subtract 8x from both sides, leaving 4y on the left side:
8x + 4y = 4 -> 4y = -8x + 4
Now, let's divide both sides by 4, so that we can have just y on the left side:
y = -2x + 1
-2 is the slope, and 1 is the y-intercept.
Answer:
Box 2 has 3 times the volume of Box 1....
Answer:
Table B
Step-by-step explanation:
